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4 years ago

Define organic chemistry

2 answers:

8 0

<span>Hello @Malikjawadarshad,

"the chemistry of carbon compounds (other than simple salts such as carbonates, oxides, and carbides)." This is the Literal Definition of Organic Chemistry, So I hope it helps. What you need to do, in this case, is state this definition, and everything you have learned to make a "Personal Definition" written by you. Do you get it? I hope so, and if not, contact me!

Thank you,
Darian D. </span>

vichka [17]4 years ago

4 0

Basically using a base of Carbon-12, it is the science that life is made up of. Carbon and other molecules are the basis of life.

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3 years ago

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Answer:

I think the answer is D.

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3 years ago

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4 years ago

Match each substance with the correct designation for the equation HSO3- + CH3NH2 <=> SO32- + CH3NH3+ HSO3- CH3NH2 SO32- C

Zanzabum

Answer:

$HSO_3^-$ : conjugate acid of $SO_3^{2-}$

$CH_3NH_2$ : conjugate base of $CH_3NH_3^+$

$SO_3^{2-}$ : conjugate base of $HSO_3^-$

$CH_3NH_3^+$ : conjugate acid of $CH_3NH_2$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

$HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+$

Here in forward reaction $CH_3NH_2$ is accepting a proton, thus it is considered as a base and after accepting a proton, it forms $CH_3NH_3^+$ which is a conjugate acid.

And $HSO_3^-$ is losing a proton, thus it is considered as an acid and after loosing a proton, it forms $SO_3^{2-}$ which is a conjugate base.

Similarly in the backward reaction, $CH_3NH_3^+$ is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms $CH_3NH_2$ which is a conjugate base.

And $SO_3^{2-}$ is accepting a proton, thus it is considered as a base and after accepting a proton, it forms $HSO_3^{-}$ which is a conjugate acid.

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3 years ago