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nekit [7.7K]
3 years ago
14

Help me please!

Chemistry
1 answer:
Bumek [7]3 years ago
8 0
Good luck kid, now mark me brainliest
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A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.6
Juli2301 [7.4K]

Answer:

\% m=40.46\%

Explanation:

Hello there!

in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:

BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl

Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:

m_{BaCl_2}=1.658gBaSO_4*\frac{1molBaSO_4}{233.38 gBaSO_4} *\frac{1molBaCl_2}{1molBaSO_4}*\frac{208.23 gBaCl_2}{1molBaCl_2}\\\\m_{BaCl_2}=1.479gBaCl_2

Thus, the mass percentage is calculated as shown below:

\% m=\frac{1.479g}{3.656g}*100 \% \\\\\% m=40.46\%

Regards!

5 0
3 years ago
A 5.00 gram sample of an oxide of lead PbxOy contains 4.33g of lead. Determine the simplest formula for the compound.
Valentin [98]
PbO2

You have to take the mass of lead in the problem, and divide by the molar mass.
When you do the same with oxygen, you get a number about twice as large as when you divide the mass of lead by the molar mass of lead. This means that the simplest formula  would be PbO2

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