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3 years ago

Quotient z on 7 Decreases on 1Decreases 7 ? ناتج قسمة Z على 7 يقل عن 1 بمقدار 7 ؟

Mathematics

1 answer:

Crank3 years ago

7 0

Answer:

pls I don't understand can u pls expatriate

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What are bookmark numbers

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Bookmark numbers helps keep track of how many bookmarks you have

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3 years ago

Read 2 more answers

A clothing store sold 4 times as many sweaters as coats. The difference in the sales was 300. How many of each were sold?

slava [35]

Sweater = 400
coats = 100
difference= 300
in an equation it would be
4x-x=300
so
3x=300
x=100
sweaters= 4x= 400
coats= x= 100

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3 years ago

Kendra can make 120 soccer kicks in 3 minutes. Jovani can make 100 soccer kicks in 4 minutes. How long will it take them to make

meriva

Answer:

Step-by-step explanation:

10 mins

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3 years ago

What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?

DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. $\frac{n(n-3)}{2}$

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

$\frac{n(n-3)}{2}$

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = $\frac{6(6-3)}{2}$

= $\frac{18}{2}$

= 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = $\frac{7(7-3)}{2}$

= $\frac{28}{2}$

= 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = $\frac{30(30-3)}{2}$

= $\frac{810}{2}$

= 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = $\frac{n(n-3)}{2}$

The number of diagonals in a n-gon is $\frac{n(n-3)}{2}$

7 0

3 years ago

Greetings. As a beginner, I'm struggling a bit to learn calculus. May I know what is the derivative of x to the power 4 step by

elena-14-01-66 [18.8K]

If you're just starting calculus, perhaps you're asking about using the definition of the derivative to differentiate $x^4$ .

We have

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x+h)^4 - x^4}h$

Expand the numerator using the binomial theorem, then simplify and compute the limit.

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x^4+4hx^3 + 6h^2x^2 + 4h^3x + h^4) - x^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} \frac{4hx^3 + 6h^2x^2 + 4h^3x + h^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} (4x^3 + 6hx^2 + 4h^2x + h^3) = \boxed{4x^3}$

In general, the derivative of a power function $f(x) = x^n$ is $\frac{df}{dx} = nx^{n-1}$ . (This is the aptly-named "power rule" for differentiation.)

3 0

2 years ago

Quotient z on 7 Decreases on 1Decreases 7 ? ناتج قسمة Z على 7 يقل عن 1 بمقدار 7 ؟​

Quotient z on 7 Decreases on 1Decreases 7 ? ناتج قسمة Z على 7 يقل عن 1 بمقدار 7 ؟