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devlian [24]
2 years ago
11

The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0 % yield. How many grams would be pro

duced from 7.45 g of butanoic acid and excess ethanol?
Express your answer in grams to three significant figures.
Chemistry
1 answer:
zepelin [54]2 years ago
4 0

7.66g of ethyl butyrate is produced.

The reaction is

CH₃CH₂CH₂COOH + CH₃CH₂OH ----> CH₃CH₂CH₂COOCH₂CH₃

  • The molar mass of butanoic acid is 88.11g/mol
  • We have 7.45g of butanoic acid
  • The moles of butanoic acid we have is 7.45/88.11 = 0.0845 mol
  • If the yield is 100%,  1 mole of butanoic acid gives 1 mole of ethyl butyrate
  • But the reaction yield is 78%
  • 1 mole of butanoic acid gives 0.78 mole of ethyl butyrate

From 0.0845 mol of butanoic acid we get 0.78 x 0.0845 = 0.66 mol of ethyl butyrate.

The molar mass of ethyl butyrate is 116.16g/mol

So 0.66 x 116.16 = 7.66g

7.66g of ethyl butyrate is produced.

Learn more about esterification here:

brainly.com/question/14028062

#SPJ10

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