What is the equation of sodium phosphide

What is the energy of a photon that emits a light of frequency 7.21 x 1014 Hz? A. 4.78 x 10-19 J B. 2.76 x 10-19 C. 1.0910-19 J

bazaltina [42]

Answer:

E = 4.78×10^−19 J

Explanation:

The chemical equation for the energy of a photon is given by:

E =hν , where h is the Planck constant and ν is the frequency.

E =hν = 6.626×10^−34 Js × 7.21×10^ 14

s−1 = 4.78 × 10^−19 J

5 0

2 years ago

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HELP PLEASE: Increasing ____ raises the boiling point of a liquid.

Art [367]

Pressure raises the boiling point

7 0

2 years ago

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Identify the neutralization reaction.

dusya [7]

The neutralization reaction among all the reactions would be the one between an acid and a base to produce salt and water.

<h3>What is a neutralization reaction?</h3>

It is a reaction involving an acid and a base to produce salt and water.

From the list of reactions, the only reaction that involves acid and a base with salt and water being the products is the first reaction.

Thus, the neutralization reaction is represented by the equation:

$2H_3PO_4 + 3Ba(OH)_2 --- > 6H_2O + Ba(PO_4)_2$

More on neutralization reactions can be found here: brainly.com/question/20038776

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4 0

2 years ago

The diagram shows two molecules (A and B) with different

Anarel [89]

Answer: chromatography

Explanation:

5 0

2 years ago

A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final

KATRIN_1 [288]

Answer : The initial temperature of the limestone is $1.05\times 10^{2}^oC$ .

Solution : Given,

Mass of limestone = 62.6 g

Mass of water = 75 g

Final temperature of limestone = $51.9^oC$

Final temperature of water = $51.9^oC$

Initial temperature of water = $23.1^oC$

The specific heat capacity of limestone = $0.921J/g^oC$

The specific heat capacity of water = $4.186J/g^oC$

The formula used :

q = m × c × ΔT

where,

q = heat required

m = mass of an element

c = heat capacity

ΔT = change in temperature

According to this, the energy as heat lost by the system is equal to the gained by the surroundings.

Now the above formula converted and we get

$q_{system}=-q_{surrounding}$

$m_{system}\times c_{system}\times (T_{final}-T_{initial})_{system}= -[m_{surrounding}\times c_{surrounding}\times (T_{final}-T_{initial})_{surrounding}]$

$m_{limestone}\times c_{limestone}\times (T_{final}-T_{initial})_{limestone}= -[m_{water}\times c_{water}\times (T_{final}-T_{initial})_{water}]$

Now put all the given values in this formula, we get

$62.6g\times 0.921J/g^{0}C \times (51.9^{0}C-T_{\text{ initial limestone}})= -[75g\times 4.186J/g^{0}C \times (51.9^{0}C-23.1^oC)]$

By rearranging the terms, we get the value of initial temperature of limestone.

$T_{\text{ initial limestone}}=104.926^{0}C=1.05\times 10^{2}^oC$

Therefore, the initial temperature of the limestone is $1.05\times 10^{2}^oC$ .

8 0

3 years ago

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