I’m done with my homework e ee was a good night I got to go to
Answer:
Doubling the voltage in this arrangement both doubles the voltage drop across the resistor and the current through it. The bulb will be much brighter.
Answer:
<h2>f=a×m</h2>
m=1800kg
1800000g×10N/kg
18000000N force is required to life the car
Answer:
20 J/g
Explanation:
In this question, we are required to determine the latent heat of vaporization
- To answer the question, we need to ask ourselves the questions:
What is latent heat of vaporization?
- It is the amount of heat required to change a substance from its liquid state to gaseous state without change in temperature.
- It is the amount of heat absorbed by a substance as it boils.
How do we calculate the latent heat of vaporization?
- Latent heat is calculated by dividing the amount of heat absorbed by the mass of the substance.
In this case;
- Mass of the substance = 20 g
- Heat absorbed as the substance boils is 400 J (1000 J - 600 J)
Thus,
Latent heat of vaporization = Quantity of Heat ÷ Mass
= 400 Joules ÷ 20 g
= 20 J/g
Thus, the latent heat of vaporization is 20 J/g
Answer:

Explanation:
Temperature of the house, 
Convert to rankine, 
Heat is extracted at 40°F i.e 
Calculate the coefficient of performance of the heat pump, COP

The minimum power required to run the heat pump is given by the formula:
...............(*)
Where the heat losses from the house, 
Substituting these values into * above
