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3 years ago

The value of y varies directly with x. If x = 16 when y = 20, find the value of y when x = 60?

Mathematics

1 answer:

son4ous [18]3 years ago

5 0

Answer:

Step-by-step explanation:

To solve this, we will use a proportion, since x and y vary directly with each other.

16 / 20 = 60 / y

<h2>Step 1: Cross-Multiply</h2>

16y = 1200

<h2>Step 2: Divide both sides by 16</h2>

16y / 16 = 1200 / 16

y = 75

<h2>Step 3: Check</h2>

16 / 20 = 60 / 75

1200 = 1200 ✅

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alukav5142 [94]

Answer:

m-(nx)

Step-by-step explanation:

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2 years ago

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Monica [59]

Answer:

Step-by-step explanation:

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3 years ago

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2 years ago

8c - c +6=48. How do I explain this with words?

N76 [4]

8c -c= 7c
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CHECK:
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3 years ago

K= 1/2mv^2<br> Solve for V

jeyben [28]

Hi there!

v = ± $\sqrt{\frac{2K}{m} }$

- - - - - - - - -

K = 1/2mv²

Isolate for the variable "v". We can begin by dividing both sides by 1/2. (Multiply by the reciprocal, or 2):

2 · K = 2 · (1/2mv²)

2K = mv²

Continue isolating by dividing both sides by "m":

2K / m = v²

Take the square root of both sides. Remember that the solution can either be positive or negative since there are positive and negative roots.

v = ± $\sqrt{\frac{2K}{m} }$

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3 years ago

Read 2 more answers

The value of y varies directly with x. If x = 16 when y = 20, find the value of y when x = 60?​

The value of y varies directly with x. If x = 16 when y = 20, find the value of y when x = 60?