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Ipatiy [6.2K]
3 years ago
15

How does weathering break down or change rocks

Chemistry
1 answer:
tatyana61 [14]3 years ago
3 0
Well weathering adds different elements to rocks which they might not be used to. For example, very hard rain & harsh winds could push a rock, causing it to fall & break off into smaller rocks.
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A sample of a compound contains 32.0g C and 8.0g H. It’s molar mass is 30.0/mol. What is the compounds molecular formula?
liraira [26]
Answer:
 
<span>Given mass of C is 32.0 grams
</span><span>Given mass of H is 8.0 grams
</span>Molar mass of C is 1212 g/mol 
Molar mass of H is 1.01 g/mol

Thus
<span><span><span><span>32.0 grams of C </span><span>8.0 grams of H </span></span><span><span>→<span>3212</span>=2.66 moles of C</span><span>→<span>81.01</span>=7.92 moles of H</span></span></span><span><span><span>32.0 grams of C </span><span>→<span>3212</span>=2.66 moles of C</span></span><span><span>8.0 grams of H </span><span>→<span>81.01</span>=7.92 moles of H</span></span></span></span>

<span>When we divide 7.92 by 2.66 we obtain 2.977 which is approximately 3. This means that the ratio of atoms of </span><span>CC</span><span> to the atoms of </span><span>HH</span><span> is 1:3.</span>

<span>Thus, empirical formula for the compound is </span><span><span>C<span>H3</span></span><span>C<span>H3</span></span></span>.

<span>Molar mass of </span><span><span>C<span>H3</span></span><span>C<span>H3</span></span></span><span> is </span><span><span>1⋅12+3⋅1.01=15.03</span><span>1⋅12+3⋅1.01=15.03</span></span><span>. Since molar mass of the compound we have to find is </span><span>3030</span><span> g/mol we have tu multiply subscripts by 2.</span>

<span>Thus, final compound is </span><span><span><span>C2</span><span>H6</span></span><span><span>C2</span><span>H6</span></span></span>.
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