Question

A cannon with a muzzle velocity of 500. meters per second fires a cannonball at an angle of 30.° above the horizontal. What is the vertical component of the cannonball's velocity as it leaves the cannon?
0.0 m/s

250. m/s

433 m/s

500. m/s

Answer 1

Complete question

A cannon with a muzzle velocity of 500. meters per second fires a cannonball at an angle of 30.° above the horizontal. What is the vertical component of the cannonball's velocity as it leaves the cannon?

A   0.0 m/s

B    250. m/s

C   433 m/s

D    500. m/s

Answer:

The correct option is  C

Explanation:

From the question we are told that

   The velocity is  $v = 500 \ m/s$

    The angle is  $\theta = 30^o$

   

Generally the vertical component of the canon ball is mathematically represented as  

          $v_y = v * cos (30 )$

=>       $v_y = 500 * cos (30 )$

=>       $v_y = 433 \ m/s$

Answer 2

Answer:

250. m/s

Explanation:

It is vertical component so you do: 500mSin(30°) = 250m/s