The two additional forces that act on the ball as it travels between the pitcher and the home plate are air resistance and gravity.
<h3>What are the forces that affect object in motion;</h3>
- Air resistance: this is the force that oppose the motion of an object in air due to frictional force
- Gravity: this is the force due to weight of the object and acts downwards.
The two additional forces that act on the ball as it travels between the pitcher and the home plate include:
- Air resistance and
- Gravitational force
<h3>How the forces affect the motion of the ball</h3>
- Air resistance oppose the motion of the ball as it travels in air.
- Gravity is the force due to weight of the ball and acts downwards.
Learn more about forces on object in motion here: brainly.com/question/10454047
As we know that spring force is given by

here we know that
F = 700 N
also we know that
k = 3500 N/m
now from above equation we will have

now we will have


so here we can say that end of the spring will be compressed by 20 cm
Light intensity and distance is
interrelated. When the distance changes, the intensity of light changes. This relationship
is called inverse-square relationship. The inverse-square relationship refers
to the fact that when distance changes, light intensity also changes: inverse
because when distance decreases, light density increases and when distance
increases, the latter decreases; square refers to the fact that light intensity
and distance is not a one-to-one relationship.
Answer:
The speed of the clay before the impact was 106.35 m/s.
Explanation:
the only force doing work on the system is the frictional force, f, the work done by f is given by:
Wf = ΔK = Kf - Ki
The clay and the block will come to rest after sliding Δx = 7.50 m, if their intial speed is v and the combined mass is m and μ is the coefficient of friction and g is gravity,then:
f×Δx = Ki
m×g×Δx×μ = 1/2×m×v^2
v^2 = 2×g×Δx×μ
= 2×(9.8)×(7.50)×(0.650)
= 95.55
v = 9.78 m/s
This is the veloty of clay and block after the clay hit the block.
if the velocity the clay and block attains after the impact is v and the initial speed of the clay is v1 and the mass is m and the speed of the block initially is V = 0 m/s and the mass is M, then according to the conservation of linear momentum:
m×v1 +M×V = v(m + M)
m×v1 = v(m + M)
v1 = v(m + M)/m
v1 = (9.78)(8.3×10^-3 + 82×10^-3)/(8.3×10^-3)
v1 = 106.35 m/s
Therefore, the speed of the clay before the impact was 106.35 m/s.
Answer:
pork, crustaceans, blood, non-halal animal-derived additives such as gelatin or suet, alcohol and any foods containing alcohol as an ingredient