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dlinn [17]
3 years ago
5

Which of the following statements is not true regarding atmospheric pressure?

Physics
2 answers:
NISA [10]3 years ago
8 0
When atmospheric pressure is higher than the absolute pressure of a gas in a container.
kondaur [170]3 years ago
4 0

Answer:

Atmospheric pressure increases with increasing altitude

Explanation:

Atmospheric pressure decreases with increasing height (altitude).

Ideally, there are no options given here with which the question can be answered, however after searching the question on google, a similar question popped up on two websites with the same set of options. doubnut.com and weegy.com and the options are;

A. Mercury and aneroid barometers are used to measure atmospheric pressure.

B. You calculate absolute pressure by adding atmospheric pressure to gauge pressure.

C. Atmospheric pressure increases with increasing altitude.

D. When atmospheric pressure is higher than the absolute pressure of a gas in a container, a partial vacuum exists in the container

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A small object carrying a charge of -2.50 nc is acted upon by a downward force of 18.0 nn when placed at a certain point in an e
Vesna [10]
Missing question in the text:
"A.What are the magnitude and direction of the electric field at the point in question?

B.<span>What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?"</span>

<span>Solution:

A) A charge q </span>under an electric field of intensity E will experience a force F  equal to:

F=qE

In our problem we have q=-2.5 nC=-2.5\cdot 10^{-9} C and F=18 nN = 18 \cdot 10^{-9} N, so we can find the magnitude of the electric field:

E= \frac{F}{q}= \frac{18\cdot 10^{-9}N}{2.5\cdot 10^{-9}C}=7.2 V/m

The charge is negative, therefore it moves against the direction of the field lines. If the force is pushing down the charge, then the electric field lines go upward.

B) The proton charge is equal to

e=1.6\cdot 10^{-19} C

Therefore, the magnitude of the force acting on the proton will be

F=eE=1.6\cdot 10^{-19} C \cdot 7.2 V/m=1.15 \cdot 10^{-18} N

And since the proton has positive charge, the verse of the force is the same as the verse of the field, so upward.

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