Answer:
the angular acceleration of the car is 1.5 rad/s²
Explanation:
Given;
initial angular velocity, = 10 rad/s
final angular velocity, = 25 rad/s
time of motion, t = 10 s
The angular acceleration of the car is calculated as follows;
Therefore, the angular acceleration of the car is 1.5 rad/s²
Answer:
The work done by gravity during the roll is 490.6 J
Explanation:
The work (W) is:
<em>Where</em>:
F: is the force
d: is the displacement = 20 m
The force is equal to the weight (W) in the x component:
<em>Where:</em>
m: is the mass of the bowling ball = 5 kg
g: is the gravity = 9.81 m/s²
θ: is the degree angle to the horizontal = 30°
Now, we can find the work:
Therefore, the work done by gravity during the roll is 490.6 J.
I hope it helps you!
Answer:
x = 0.0537 m or 5.37 cm
Explanation:
Given:
spring constant'k'= 4900 N/m
radius 'r' =0.029 m
Area 'A' =r²π = 0.029²π => 2.6 x m²
Here, Pressure 'P' is given by,
Pressure = Force / Area
And we know that, for a spring :
F = kx, where k is the spring constant and x is the change in length.
P = kx/A
As P = 101325 Pa
101325 = 4900x / ( 2.6 x )
x = 0.0537 m or 5.37 cm