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Degger [83]
1 year ago
13

Force Problem: Four concurrent forces are applied to a 5 Kg mass: 50 N North, 25 N East, 35 N South, and 35 N West.

Physics
1 answer:
Kaylis [27]1 year ago
6 0

A) Net horizontal force:
Fx= -35 + 25 + -10N

Net vertical force
Fy= 50 - 35 = 15N

Net force
F^2 = fX^2 +Fy^2
F= 18N

B.) Acceleration of system
a=18/5=3.6m/s^2

C). Equilibriant force must be equal to the net force above
F1= 18N

D.) Acceleration becomes half
a1= a/2 =1.8m/s^2

E.) Equilibrant force also doubles
F" = 2F' = 36N

To learn more about Force, click on the link
brainly.com/question/12785175

#SPJ13

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An electron with kinetic energy 2.9 keV moving along the positive direction of an x axis enters a region in which a uniform elec
Vladimir79 [104]

The electric force on the electron is opposite in direction to the electric field E. E points in the -y direction, so the electric force will point in the +y direction. The magnitude of the electric force is given by:

F = Eq

F = electric force, E = electric field strength, q = electron charge

We need to set up a magnetic field such that the magnetic force on the electron balances out the electric force. Since the electric force points in the +y direction, we need the magnetic force to point in the -y direction. Using the  reversed right hand rule, the magnetic field must point in the -z direction for this to happen. Since the direction is perpendicular to the +x direction of the electron's velocity, the magnetic force is given by:

F = qvB

F = magnetic force, q = charge, v = velocity, B = magnetic field strength

The electric force must equal the magnetic force.

Eq = qvB

Do some algebra to isolate B:

E = vB

B = E/v

Let's solve for the electron's velocity. Its kinetic energy is given by:

KE = 0.5mv²

KE = kinetic energy, m = mass, v = velocity

Given values:

KE = 2.9keV = 4.6×10⁻¹⁶J

m = 9.1×10⁻³¹kg

Plug in and solve for v:

4.6×10⁻¹⁶ = 0.5(9.1×10⁻³¹)v²

v = 3.2×10⁷m/s

B = E/v

Given values:

E = 7500V/m

v = 3.2×10⁷m/s

Plug in and solve for B:

B = 7500/3.2×10⁷

B = 0.00023T

B = 0.23mT

3 0
4 years ago
A total of 875 J of work was done when a force of 175 N was exerted on a box to move it. How far was the box moved
Vladimir [108]
Work = Force times Distance
W = Fd

Given W = 750J, F = 125N;

750 = 125d

Solving for d:
d = 750/125
d = 6

The box moved a distance of 6 meters.
3 0
2 years ago
Name a sex linked genetic disorder
notsponge [240]
One disorder would be ''Unisex'' of where a child born can suffer a disorder of where they are born with both male and female genitals on one gender. Doctors and the hospital can surgically remove the extra genital from the child.
5 0
3 years ago
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The rate at which energy is transferred is called
makvit [3.9K]

Answer:

The rate at which energy is transferred is called power and the amount of energy that is usefully transferred is called efficiency.

6 0
3 years ago
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You see a total eclipse of the sun. Three Saros cycles later, you find yourself at the same location.
alukav5142 [94]

Answer:

The correct answer is B. You would not have to travel far to see another total eclipse  .

Explanation:

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