Where do the electrons come from that produce heat and light in a light bulb?

A 40-lb container of peat moss measures 14× 20× 30 in. A 40-lb container of topsoil has a volume of 1.9 gal. Calculate the avera

Viktor [21]

The average density of the peat moss in units of g/cm³ is 2.52 g/cm³

<h3>How to convert 40 lb to grams (g)</h3>

We'lol begin by converting 40 lb to grams (g). This can be obtained as follow:

1 lb = 453.592 g

Therefore,

40 lb = (40 × 453.592) / 1 lb

40 lb = 18143.68 g

<h3>How to convert 1.9 gal to cm³</h3>

We can convert 1.9 gal to cm³ as follow:

1 gal = 3785.41 cm³

Therefore,

1.9 gal = (1.9 gal × 3785.41 cm³) / 1 gal

1.9 gal = 7192.279 cm³

<h3>How to determine the density </h3>

The density can be obtained as follow:

Mass = 18143.68 g
Volume = 7192.279 cm³
Density =?

Density = mass / volume

Density = 18143.68 / 7192.279

Density = 2.52 g/cm³

Learn more about density:

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8 0

2 years ago

What controls traits in organisms? A.Cell Membrane B.Cell Wall C.Genes D.Punnett Square

BARSIC [14]

Answer:

I believe it's C (the genes)

3 0

3 years ago

Read 2 more answers

The reaction of NO2 with ozone produces NO3 in a second-order reaction overall.

Brilliant_brown [7]

Answer : The rate of reaction is,

$Rate=4.77\times 10^{-19}M/s$

The appearance of $NO_3$ is, $4.77\times 10^{-19}M/s$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$NO_2(g)+O_3(g)\rightarrow NO_3(g)+O_2(g)$

The rate law expression will be:

$Rate=k[NO_2][O_3]$

Given:

Rate constant = $k=1.69\times 10^{-4}M^{-1}s^{-1}$

$[NO_2]$ = $1.77\times 10^{-8}M$

$[O_3]$ = $1.59\times 10^{-7}M$

$Rate=k[NO_2][O_3]$

$Rate=(1.69\times 10^{-4})\times (1.77\times 10^{-8})\times (1.59\times 10^{-7})$

$Rate=4.77\times 10^{-19}M/s$

The expression for rate of appearance of $NO_3$ :

$\text{Rate of reaction}=\text{Rate of appearance of }NO_3=+\frac{d[NO_3]}{dt}$

As, $\text{Rate of reaction}=4.77\times 10^{-19}M/s$

So, $\text{Rate of appearance of }NO_3=+\frac{d[NO_3]}{dt}=4.77\times 10^{-19}M/s$

Thus, the appearance of $NO_3$ is, $4.77\times 10^{-19}M/s$

7 0

3 years ago

How many Atoms of Oxygen are in water H20? explain how u know

blagie [28]

There are ALOT because they would always come in and out and they will burst which creates more so techneclly there are infinate

3 0

3 years ago

Read 2 more answers

A system gains 652 kJ of heat, resulting in a change in internal energy of the system equal to +241 kJ. How much work is done?

levacccp [35]

Answer:

-411 kj

Explanation:

We solve by using this formula

∆U = ∆Q + ∆W

This formula is the first law of thermodynamics

Change in internal energy U = +241

Heat gained by system Q = 652

Putting the value into the equation

+241 = 652 + W

Workdone = 241 - 652

Workdone = -411 kj

Since work done is negative it means that work was done by the system

3 0

2 years ago