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TiliK225 [7]
3 years ago
10

1) According to Bohr's model of the atom, in which orbitals do electrons have the most energy?

Chemistry
2 answers:
Alex Ar [27]3 years ago
7 0

The orbitals closest to the nucleus is the orbital wih the lowest energy. This is according to the basic rules stating that the energy of the shells as its principal quantum number increases, also increases. Thus the answer in 1 is B. Valence electrons are found in the outermost electron shell, on the other hand. 
FinnZ [79.3K]3 years ago
6 0

The answer is:

1) Outermost orbitals have the most energy.

The explanation:

In Bohr model we can see that the highest energy level is found in the outermost orbital , when the first orbital form and make a shell around the nucleus and its principal quantum number which has the symbol (n) is = 1

So the other orbital away from the nucleus is gradually assigned values:

n = 2  

n= 3

n=4

etc

and  the most stable and the lowest energy level is found in the innermost orbit.  

2) valence electrons located in the outermost electrons shell.

The explanation:

when:  

The number of electrons in the outermost shell of an atom gets its reactivity or tendency from it to form and make the chemical bonds with the other atoms.

This outermost shell is called the valence shell, and the electrons found in this shell are called valence electrons.

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The main idea of an essay is usually portrayed in the thesis.
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The density of Mg is 1.74g/cm3. The density of strontium is 2.60g/cm3. What would you expect the density of Ca to be?
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The density of Ca will be between that of Mg and Sr

Explanation:

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Density is an intensive property of matter which describes the amount of matter(mass) per volume of a substance.

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6 0
3 years ago
A 51.24-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 liters of solution. How many mL of this solution must be d
g100num [7]

Answer:

0.40 L

Explanation:

Calculation of the moles of Ba(OH)_2 as:-

Mass = 51.24 g

Molar mass of Ba(OH)_2 = 171.34 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{51.24\ g}{171.34\ g/mol}

Moles= 0.2991\ mol

Volume = 1.20 L

The expression for the molarity is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.2991\ mol}{1.20\ L}=0.24925\ M

Thus,

Considering

Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

Molarity_{working\ solution}=0.100\ M

Volume_{working\ solution}=1\ L

Volume_{stock\ solution}=?

Molarity_{stock\ solution}=0.24925\ M

So,  

0.100\ M\times 1\ L=0.24925\ M\times Volume_{stock\ solution}

Volume_{stock\ solution}=\frac{0.100\times 1}{0.24925}\ L=0.40\ L

<u>The volume of 0.24925M stock solution added = 0.40 L </u>

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