1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Juliette [100K]
2 years ago
5

Calculate the molarity of the two solutions.

Chemistry
1 answer:
zmey [24]2 years ago
4 0

Answer:

a) 0.100 M

b) 0.395 M

Explanation:

a) Calculate the molarity of a solution that contains 0.200 moles of NaOH (solute) in 2.00 L of solution

We will use the following expression for molarity.

[NaOH] = moles of solute / liters of solution

[NaOH] = 0.200 mol/2.00 L = 0.100 M

b) Calculate the molarity for a solution that contains 15.5 g of NaCl (solute, 58.44 g/mol) in 671 mL of solution

We will use the following expression for molarity.

[NaCl] = mass of solute / molar mass of solute × liters of solution

[NaCl] = 15.5 g / 58.44 g/mol × 0.671 L = 0.395 M

You might be interested in
Define atomic size, electronegativity, and ionization energy and explain how they vary at different places on the periodic table
anygoal [31]
As you move down the periodic table, atomic size increases (due to the number of electron shells of an atom increasing). So in Group 1, H has the smallest atomic size, while Fr has the largest.

Ionization energy tends to decrease as you go down a group, and increase as you go from left to right on the periodic table. (As you go down, the atomic size/radius increases, so the outermost electrons are held less tightly to the nucleus, causing a lower ionization energy.)

Electronegativity relates to ionization energy. Elements with a higher ionization energy will have higher electronegativity. Therefore, as you move down the periodic table, electronegativity decreases, while as you move from left to right on the periodic table, electronegativity increases. 
5 0
3 years ago
If the pressure of 125 cm3 of nitrogen gas at 100 °c decreases from 885 torr to 225torr, what is the final volume? assume temper
navik [9.2K]
Suppose the Gas is acting ideally, Then, According to Ideal Gas Equation;

                                               P₁ V₁  =  P₂ V₂    ----- (1)
Data Given:
                  P₁  =  885 torr

                  V₁  =  125 cm³

                  P₂  =  225 torr

                  V₂  =  ?

Puting values in eq, 1;

                                     V₂  =  P₁ V₁ / P₂

                                     V₂  =  (885 torr × 125 cm³) ÷ 225 torr

                                     V₂  =  491.66 cm³
4 0
3 years ago
Is the speed on this graph increasing or constant?
solong [7]

Answer:

The speed is constant.

Explanation:

The equation for a straight-line graph is  

<em>y</em> = m<em>x</em> + b

where m and b are constants.

m is the <em>slope</em> of the line and b is the <em>y-intercept. </em>

If we change the variables, the equation becomes

<em>d</em> = m<em>t</em> + b

m = \frac{\Delta d}{\Delta t} = = \frac{\text{ distance}}{\text{time}} = \text{speed}

Since m is constant, so is the speed.

7 0
2 years ago
Read 2 more answers
Can you help me please​
melomori [17]

Answer:

I don't get yuh language kindly

6 0
3 years ago
A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58
Scilla [17]

Answer:

\% O=27.6\%

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}  =0.218molC

- Moles of hydrogen are contained in the 3.922 grams of water:

n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO

Finally, we compute the percent by mass of oxygen:

\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%

Regards.

5 0
3 years ago
Other questions:
  • Help me please !!!
    15·1 answer
  • A sample of 2.0 moles of a metal reacts completely with excess oxygen to form 62.0 g of M2O. What element is represented by the
    10·1 answer
  • Why is it harder to remove an inner shell electron than a valence electron from an atom
    14·2 answers
  • What is gentle breeding
    11·1 answer
  • What is the ph of a 2.7 m solution of hclo4?
    10·1 answer
  • Which molecule could form a coordinate covalent bond with a proton (h )?
    12·2 answers
  • Explain why the following primary substrate undergoes SN1 very rapidly (the OTs is the leaving group)?
    7·1 answer
  • If a neutral atom has a mass of 12 amu and an atomic number of 5, determine the number of protons, neutrons, and electrons in th
    14·2 answers
  • Convert 60 grams of nitrogen gas (N2) to liters.
    6·1 answer
  • How many atoms of iron are there in 5.00 g of iron?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!