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Juliette [100K]
3 years ago
5

Calculate the molarity of the two solutions.

Chemistry
1 answer:
zmey [24]3 years ago
4 0

Answer:

a) 0.100 M

b) 0.395 M

Explanation:

a) Calculate the molarity of a solution that contains 0.200 moles of NaOH (solute) in 2.00 L of solution

We will use the following expression for molarity.

[NaOH] = moles of solute / liters of solution

[NaOH] = 0.200 mol/2.00 L = 0.100 M

b) Calculate the molarity for a solution that contains 15.5 g of NaCl (solute, 58.44 g/mol) in 671 mL of solution

We will use the following expression for molarity.

[NaCl] = mass of solute / molar mass of solute × liters of solution

[NaCl] = 15.5 g / 58.44 g/mol × 0.671 L = 0.395 M

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Answer:

a. 10.0 g

Explanation:

The molar mass of NaOH is 39.997 grams which was calculated by adding the molar mass of Sodium, Oxygen, and Hydrogen 22.990 + 15.999 + 1.008 = 39.997. But before we do anything with this number we must first convert 1.50 * 10^{23} molecules to moles. We can do this by dividing by Avogadro's number or 6.022*10^{23}  ( \frac{1.50*10^{23}}{6.022*10^{23}} = 0.24909 moles). We then convert moles to grams by multiplying by the molar mass of NaOH, (0.24909 * 39.997 = 9.96 grams). This is almost exactly 10 and the margin of error is likely due to the original numbers not being precise enough.

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How should I write balanced net ionic equation for this reaction?
Maksim231197 [3]

Answer:

Explanation:

Assumptions

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