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Nataly [62]
3 years ago
8

Help me please..

Physics
1 answer:
Nana76 [90]3 years ago
6 0
It’s B, 15 miles per hour
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estimate the number of table tennis balls that would fit (without being crished) into a room that is 4 m long, 4 m wide, and 3 m
Mumz [18]
The diameter of a ball is 3.8 cm.

Because 400/3.8 = 105.26,
each dimension of 400 m can accommodate 105 balls.
Similarly, because 300/3.8 = 78.95,
each dimension of 300 m can accommodate 78 balls.

The total number of balls is 105*105*78 = 859,950

Answer: 859,950 balls

4 0
3 years ago
a satellite maintains an orbit equidistant from the earth at all points along its orbital path hiw is the satellite affected by
Paraphin [41]
ANY closed orbit exists because of the centripetal force of gravity.
Without the force of gravity, the satellite would simply sail away
in a straight line.

The orbit you're describing happens to be a circular orbit, but it
doesn't have to be circular.
5 0
4 years ago
In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th
diamong [38]

Answer:

3.77 Hz

Explanation:

The beat frequency that is heard can be calculated using the following equation:

f_{b} = f_{1} - f_{2}

<u>Where:</u>

f₁ = 110 Hz

f_{2} = \frac{f_{1}}{\sqrt{\frac{T_{1}}{T_{2}}}}

<u>With:</u>

<em>T₁ = 594 N        </em>

<em>T₂ = 554 N </em>

f_{2} = \frac{f_{1}}{\sqrt{\frac{T_{1}}{T_{2}}}} = \frac{110 Hz}{\sqrt{\frac{594 N}{554 N}}} = 106.23 Hz

Hence, the beat frequency is:        

f_{b} = f_{1} - f_{2} = 110 Hz - 106.23 Hz = 3.77 Hz      

Therefore, the beat frequency that is heard when the hammer strikes the two strings simultaneously is 3.77 Hz.

I hope it helps you!                              

3 0
4 years ago
2a. A wave has a frequency of 50 Hz and a wavelength of 0.10 m. How do you find the wave speed? *
KIM [24]
D is it so go with it
5 0
3 years ago
A body is projected vertically upwards with a velocity of 10m/s from a vertically upward position at height h another body is dr
RoseWind [281]

Answer:

0.25 second  

Explanation:

Given :

Velocity, v = 10 m/s

The height,

$ h = \frac{v^2}{2g} $

$ h = \frac{10^2}{2\times 9.8} $

   = 5 m

Therefore the time at which both the bodies meet is

$ t = \frac{h}{v+v} $

$ t = \frac{5}{10+10} $

$ t = \frac{5}{20}  = 0.25$

So, time taken is 0.25 seconds

3 0
3 years ago
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