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A 40.0-μFcapacitor is connected across a 60.0 Hz generator. An inductor is then connected in parallel with the capacitor. What i

amm1812

Answer:

The value of the inductance is 175.9 mH.

Explanation:

Given that,

Capacitor $C= 40.0\ \muF$

Frequency = 60.0 Hz

The inductor and capacitor is connected in parallel, the voltage across each of these elements is the same.

We have,

$V_{L}=V_{C}$

Using ohm's law

$I_{rms}\times X_{L}=I_{rms}\times X_{C}$

$X_{L}=X_{C}$

$2\pi f L=\dfrac{1}{2\pi f C}$

$L=\dfrac{1}{4\pi^2\times f^2\times C}$

Put the value into the formula

$L=\dfrac{1}{4\times\pi^2\times60.0^2\times40\times10^{-6}}$

$L=0.1759\ H$

$L=175.9\times10^{-3}\ H$

$L=175.9\ mH$

Hence, The value of the inductance is 175.9 mH.

5 0

4 years ago

A moving walkway at the airport moves a 120Kg person 35m in 150s. How much power did this require?

Alexxx [7]

The amount of power required to move the 120 Kg person to a distance of 35 m in 150 s is 274.4 W

<h3>How to determin the power</h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = force (F) × distance (d)

Therefore,

P = Fd / t

With the above formula, we can obtain the power as follow:

Mass (m) = 120 Kg
Distance (d) = 35 m
Time (t) = 150 s
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) = mg = 120 × 9.8 = 1176 N
Power (P) = ?

P = Fd / t

P = (1176 × 35) / 150

P = 41160 / 150

P = 274.4 W

Thus, the power is 274.4 W

Learn more about power:

brainly.com/question/20353916

#SPJ1

6 0

1 year ago

Calculate the acceleration of a car (in km/h.s)<br> that can go from rest to 100 km/h in 10s

Over [174]

Answer:

10 km/h/s

Explanation:

Acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (100 km/h − 0 km/h) / 10 s

a = 10 km/h/s

8 0

4 years ago

A 1800 kg car moves along a horizontal road at speed v₀ = 18.4 m/s. The road is wet, so the static friction coefficient between

slamgirl [31]

Answer:

The shortest possible distance is $|s| = 91.9 \ m$

Explanation:

From the question we are told that

The mass of the car is $m = 1800 \ kg$

The speed along the horizontal road is $v_o =u = 18.4 \ m/s$

The static friction coefficient is $\mu_s = 0.188$

The kinetic friction coefficient is $\mu_k = 0.1316$

Generally the static frictional force acting on the car is mathematically represented as

$F_f = m * g * \mu_s$

Generally the force propelling the car is mathematically represented as

$F = m * a$

Here a is the maximum acceleration

at the point which the car stops ,

$F = F_f$

=> $m * g * \mu_s = ma$

=> $g * \mu_s =a$

=> $a = 9.8 * 0.188$

=> $a = 1.8424 \ m/s^2$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here v is the final velocity of the car and the value is zero given that the car comes to rest

So

$0^2 = 18.4^2 + 2* 1.8424 s$

=> $s = - \frac{18.4^2}{2 * 1.8424}$

=> $|s| = 91.9 \ m$

6 0

3 years ago

How long does it take for a Ford Econoline van moving at 39.5 m/s to travel 600 m?

Andrej [43]

Answer: B. 15.2s

Explanation: 600/39.5 = about 15.2

6 0

4 years ago