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natulia [17]
3 years ago
8

Explain why a metal box does not fall through a table to the floor???

Physics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

the table is strong enough to hold the metal

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During a rainy day, as a result of colliding clouds an observer saw lighting and a heard thunder sound. The time between seeing
hodyreva [135]

Answer:

d = 1700 meters

Explanation:

During a rainy day, as a result of colliding clouds an observer saw lighting and a heard thunder sound.  The time between seeing the lighting and hearing the sound was 5 second, t = 5 seconds

Speed of sound, v = 340 m/s (say)

Let d is the distance of the colliding cloud from the observer. The distance covered by the object. It is given by :

d=v\times t

d=340\ m/s\times 5\ s  

d = 1700 meters

So, the distance of the colliding cloud from the observer is 1700 meters. Hence, this is the required solution.    

8 0
3 years ago
Which requires more work, lifting a 10.0kg load a vertical distance of 2m or lifting a 5.0kg load a distance of 4m?
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For each load,  Work = (mass) x (gravity) x (distance .

Bigger load:      Work = (10 kg) x (9.8 m/s²) x (2 m) = 196 joules .

Smaller load:    Work = (5 kg)  x  (9.8 m/s²)  x  (4 m) = 196 joules.

The work required is equal in both cases.

The mass ratio of  2:1  is exactly balanced by
the height ratio of  1:2 .

6 0
3 years ago
The impact of the type of material of which the slope is made on acceleration
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 The impact of the material type with which the slope is made affects the acceleration. Acceleration will be higher and smoother if the material of the slope surface is smoother as opposed to a texture which is not smooth. Smoother surface allows more acceleration because it will have less friction and resistance. Otherwise the friction will slow the object down for example a grassy ground will have more friction than a well maintained marble floor. 

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Which, if any, of the heat engines violate(s) the second law of thermodynamics?
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The second law states that the total entropy can never decrese over time for an isolated system
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3 years ago
Two equally charged, 1.00 g spheres are placed with 2.00 cm between their centers. when released, each begins to accelerate at 2
Leya [2.2K]
1) Force = m*a = 1.00 g * (1kg / 1000 g) * 225 m/s^2 = 0.225 N

2) Charge

Force = K (charge)^2 /(distance)^2 => charge = √ [Force * distance^2 / k]

k = 9.00 * 10^9 N*m^2 / C^2

charge = √ [0.225 N * (0.02 m)^2 / 9.00* 10^9 N*m^2 / C^2 ]

charge = 0.0000001 C = 0.0001 mili C
3 0
3 years ago
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