The time after it starts spinning, that the box will slip off is 0.1 s.
<h3>Apply the principle of conservation of angular momentum</h3>
I₁ω₁ - I₂ω₂ = 0
I₁ω₁ = I₂ω₂
where;
- I₁ is initial moment of inertia
- I₂ is final moment of inertia
- ω₁ is initial angular speed
- ω₂ is final angular speed
The final angular speed when the box slides off;
ω₂ = I₁ω₁ / I₂
ω₂ = [0.5(m₁ + m₂)(R + r)²] / (0.5MR²)
ω₂ = [0.5(30 + 0.3)(3.1 + 1.4)²] / (0.5 x 30 x 3.1²)
ω₂ = 2.13 rad/s
Time taken for the for box to slide off;
τ = Iα
τ = I(ω/t)
τ = (Iω)/t
t = (Iω)/τ
t = (0.5 x 0.3 x 1.4² x 2.13)/6
t = 0.1 s
Thus, the time after it starts spinning, that the box will slip off is 0.1 s.
Learn more about moment of inertia here: brainly.com/question/3406242
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Answer:
1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.
solution
element
mixture
compound
2.
Which of the following materials is a substance?
air
gasoline
stainless steel
silver
3.
The first figure in a properly written chemical symbol always is _____.
boldfaced
capitalized
italicized
underlined
4.
Which of the following represents a compound?
H
H-3
H2O
O-16
5. What do chemical symbols and formulas represent, respectively?
elements and compounds
atoms and mixtures
compounds and mixtures
elements and ions
Explanation:
Answer:
SI unit for energy is Joules.
in base units it will be:
1 J = 1 N·m = <u>1 kg·m²/s²</u>
Answer:
the correct one is B ₊₁e
Explanation:
In the radioactive emission process there are three fundamental types, enision of alpha particles, emission of beta rays and emission of high energy photons.
In beta particle emission processes, a neutron decomposes, emitting an electron and an antineutrino, so the mass number of the nucleus does not change, but the atomic number increases by one unit.
Another possibility is the emission of a positron (positive charge) plus a neutrino, in this case the atomic mass remains constant and the atomic number decreases by one unit.
The second beta emission process if it describes the situation presented, when reviewing the answers the correct one is B
Answer:
a ) 4.5 N.s
b) V =5 m/s
Explanation:
given,
mass of rifle(M) = 0.9 kg
mass of bullet(m) = 6 g = 0.006 kg
velocity of the bullet(v) = 750 m/s
a) momentum of bullet = m × v
= 750 × 0.006
= 4.5 N.s
b) recoil velocity
m × u + M × U = m × v + M × V
0 + 0 = 0.006 × 750 - 0.9 × V
V = 
V =5 m/s