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2 years ago

What is the density of a rock with a mass of .235kg

Physics

1 answer:

Andre45 [30]2 years ago

4 0

Answer:

where is volume? formula of density is: mass/volume so volume must be there

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Which of the following is not a dwarf planet?

Fantom [35]

The correct answer is (a.) Hydra. Hydra is not a dwarf planet, instead, it is the moon of the dwarf planet, Pluto. There are only four accepted dwarf planets by the International Astronomical Union which were the Haumea, Pluto, Eris, and Makemake.

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3 years ago

In which type of wave do air particles move together or apart parallel to the direction of the wave?

Kitty [74]

C. Sound waves is the answer =P

7 0

3 years ago

A water main pipe of diameter 10 cm enters a house 2 m below ground. A smaller diameter pipe carries water to a faucet 5 m above

Lemur [1.5K]

Explanation:

Given that,

Diameter = 10 cm

Distance = 2 m

Speed $v_{1}= 2\ m/s$

Speed $v_{2}=7\ m/s$

Pressure in main pipe $P_{1}=2\times10^{5}\ Pa$

(I). We need to calculate the diameter

Using equation of continuity

$Av_{1}=Av_{2}$

$\pi(\dfrac{d_{1}}{2})^2\times v_{1}=\pi(\dfrac{d_{2}}{2})^2\times v_{2}$

$(\dfrac{10}{2})^2\times2=(\dfrac{d_{2}}{2})^2\times7$

$d_{2}=\sqrt{\dfrac{25\times2\times4}{7}}$

$d_{2}=5.345\ cm$

(II). We need to calculate the pressure the gauge pressure

Using Bernoulli equation

$P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho g h_{2}$

$P_{2}=P_{1}+\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)-\rho g(h_{1}-h_{2})$

$P_{2}=2\times10^{5}+\dfrac{1}{2}\times1000(4-49)-1000\times 9.8\times(5)$

$P_{2}=1.28500\times10^{5}\ Pa$

(III). If it is possible to carry water to a faucet 17 m above ground,

Using Bernoulli equation

$P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh=P_{3}+\dfrac{1}{2}\rho v_{3}^2+\rho g h_{3}$

$P_{3}=P_{1}+\dfrac{1}{2}\rho v_{1}^2-\rho g(h_{1}-h_{3})$

Here, $h_{3}=0$

Put the value in the equation

$P_{3}=2\times10^{5}+\dfrac{1}{2}\times1000\times4-1000\times 9.8\times17$

$P_{3}=3.5400\times10^{5}\ Pa$

Hence, This is required solution.

7 0

3 years ago

A 50 kg wagon is pulled with a 100 N force. If the force is increased to 200 N, how quickly will the wagon accelerate? 1 m/s2 2

Katen [24]

4 m/s2

I hope this helps!

3 0

3 years ago

Read 2 more answers

A transverse sinusoidal wave is moving along a string in the positive direction of an x axis with a speed of 89 m/s. At t = 0, t

earnstyle [38]

Answer:

The answer is below

Explanation:

Given that:

y = transverse displacement = 4.2 cm = 0.042 m at x = 0 and t = 0.

Speed = v = 89 m/s, maximum transverse speed of the string particle = $u_m$ = 16 m/s.

ω = $u_m$ / $y_m$ = 16 / 0.42 = 380.95 rad/s

a) Frequency = ω/2π = 380.95 / 2π = 60.63 Hz

b) Wavelength (λ) = speed / frequency

λ = v / f = 89/63.66= 1.468 m

c) Using the wave equation:

$y=y_msin(kx \pm wt \pm \phi)\\y=0.042,t=0,x=0\\\\Hence\\y_m=0.042\ m$

d) Wave number k is given by:

k = 2π / λ = 2π / 1.468 = 4.28 rad/s

e) The angular velocity is given by:

ω = $u_m$ / $y_m$ = 16 / 0.42 = 380.95 rad/s

f) Using the wave equation:

$y=y_msin(kx \pm wt \pm \phi)\\\\y=0.042,t=0,x=0,y_m=0.042\\\\Hence\\0.042=0.042sin(4.28(0)\pm 380.95(0)\pm \phi)\\\\sin\phi=1\\\\\phi=\frac{\pi}{2} \\\\y=0.042sin(4.28x\pm 380.95t\pm \frac{\pi}{2})$

g) Since the wave is in the positive x direction, hence ω is negative

4 0

3 years ago