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Hoochie [10]
3 years ago
11

create a poem that incorporates those ten words. Feel free to make it as silly as you like! MINIMUM of 6 lines with a MINIMUM of

5 words and 10 should come from your book. These do not have to rhyme, but can if you wish.
Physics
1 answer:
Luba_88 [7]3 years ago
8 0

I could make a poem for you if you actually gave the words...... what 10 words do i need to incorporate???☹︎

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Is electrical conductivity?
expeople1 [14]

Answer:

can't tell if this is question, it is not written correctly

Explanation:

Electrical conductivity is the measure of a material's ability to allow the transport of an electric charge. Its SI is the siemens per meter, (A2s3m−3kg−1) (named after Werner von Siemens) or, more simply, Sm−1. It is the ratio of the current density to the electric field strength.

8 0
3 years ago
A bird flies 2 km to the south then 0.2 km to the north . What is the displacement of the bird?
lidiya [134]
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8 0
3 years ago
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The picture below shows Lake Jackson in Florida
nikklg [1K]
The reason why Lake Jackson disappeared is A. opening of a sinkhole.
Pollution, high atmospheric temperature, and absorption of water by the land aren't enough for an entire lake to disappear, however, a sinkhole may contribute to that. There are two major depressions (sinkholes) in this lake in Florida, and they even have their own names - Porter Sink and Lime Sink. 
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3 years ago
If the real gi tract is 9 meters long, the model you created is what fraction of the real one
Sedbober [7]

Answer:

a

Explanation:

a

7 0
3 years ago
If the work required to speed up a car from 11 km/h to 21 km/h is 6.0×103 J , what would be the work required to increase the ca
goblinko [34]

Explanation:

We need convert the velocities first to m/s and we get the following:

v2 = 21 km/hr = 5.8 m/s

v1 = 11 km/hr = 3.1 m/s

We need to find the mass of the car also for later use do using the work-energy theorem:

delta \: w =  \frac{1}{2} m(v \frac{2}{2}  - v\frac{2}{1} )

6.0x10^3 J = (0.5) m [(5.8)^2 - (3.1)^2]

or

m = 499.4 kg

Now we determine work needed delta W to change its velocity from 21 km/hr to 33 km/hr

v2 = 33 km/hr = 9.2 m/s

v1 = 21 km/hr = 5.8 m/s

delta W = (0.5)(499.4)[(9.2)^2 - (5.8)^2]

= 1.3 x 10^4 J

6 0
3 years ago
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