Answer:
The surface gravity is inversely proportional to the square of the radius of the planet
Explanation:
The gravity at the surface of a planet is given by:
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
We see from the formula that the surface gravity is inversely proportional to the square of the radius of the planet, R.
At the Earth's surface, the value of the surface gravity is approximately 9.81 m/s^2.
Answer:
311,850 N
Explanation:
We can solve the problem by using Newton's second law:
where
F is the net force applied on an object
m is the mass of the object
a is its acceleration
For the object in this problem,
m = 27 kg
Substituting, we find the force required:
Answer:
909.1 m
Explanation:
Rate of temperature increase with 100 m elevation = 1°C
h = Maximum Height
Adiabatic lapse rate = -0.65°C/100 m
We have the relation
The maximum height is 909.1 m
Answer:
KE2 = 2 KE1
1/2 M V2^2 = 2 * (1/2 M V1^2)
V2^2 = 2 V1^2
V2 = V1
Since momentum = M V the momentum increases by
Answer:
Magnitude the net torque about its axis of rotation is 2.41 Nm
Solution:
As per the question:
The radius of the wrapped rope around the drum, r = 1.33 m
Force applied to the right side of the drum, F = 4.35 N
The radius of the rope wrapped around the core, r' = 0.51 m
Force on the cylinder in the downward direction, F' = 6.62 N
Now, the magnitude of the net torque is given by:
where
= Torque due to Force, F
= Torque due to Force, F'
Now,
The net torque comes out to be negative, this shows that rotation of cylinder is in the clockwise direction from its stationary position.
Now, the magnitude of the net torque: