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Delicious77 [7]
3 years ago
10

If the coefficient of static friction between your friend and the car seat is 0.500 and you keep driving at a constant speed of

21.0 m/sm/s , what is the maximum radius you could make your turn and still have your friend slide your way?
Physics
1 answer:
Rasek [7]3 years ago
7 0

Answer:

90m

Explanation:

Let g = 9.8 m/s2. The friction is the product of normal force and its coefficient, and normal force is equal to gravity

F_f = \mu N = \mu mg

The acceleration caused by friction, according to Newton's 2nd law:

a_f = F_f / m = \mu g = 0.5 * 9.8 = 4.9 m/s^2

For the friend to slide over, then the centripetal acceleration must be equal to friction acceleration.

Since you are driving at a constant speed of 21 m/s, then your maximum radius of curvature can be calculated using the following formula:

a_c = a_f = v^2/r = 4.9

r = v^2/4.9 = 21^2/4.9 = 90 m

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Yes, the ions can exit slit P without being deflected, if the electric field strength is 170.6 N/C

Explanation:

When the ions are inside the container, they are subjected to two forces, with directions opposite to each other:

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The ions will move straight and undeflected if the two forces are equal and opposite. By using Fleming Left Hand rule, we notice that the magnetic force on the (negative) ions point upward: this means that the electric field must be also upward (so that the electric force on the ions is downward). Then, the two forces are balanced if

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Therefore, if the speed of the ions is equal to this ratio, the ions will go undeflected.

We can even calculate the value of E at which this occurs. In fact, we know that the ions are earlier accelerated by a potential difference V=-3000 V, so we have that their kinetic energy is given by the change in electric potential energy:

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Solving for v, the speed,

v=\sqrt{\frac{2qV}{m}}=\sqrt{\frac{2(-2.0\cdot 10^{-19})(-3000)}{2.84\cdot 10^{-20}}}=205.6 m/s

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The strength of the electric field must be

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Learn more about electric and magnetic fields:

brainly.com/question/8960054

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Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

<em>We have a formula for such condition,</em>

Q=m.c.\Delta T.....................................(1)

where:

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<u>Proving mathematically:</u>

<em>According to the given conditions</em>

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  • equal heat is supplied to both the solutions, i.e. Q_A=Q_B
  • specific heat of solution A, c_{A}=2.0 J.g^{-1} .\degree C^{-1}
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Now, putting the above values

Q_A=Q_B

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