Answer:
a) the three longest wavelengths = 4.8m, 2.4m, 1.6m
b) what is the frequency of the third-longest wavelength = 75Hz
Explanation:
The steps and appropriate formula and substitution is as shown in the attached file.
 
        
             
        
        
        
The solution for the problem is:
Constant speed means Fnet = 0. 
Let m = mass of wood block and Θ = angle of ramp; then if µk = 0.35 …
The computation would be:
Fnet = 0 = mg (sin Θ) - (µk) (mg) (cos Θ) 
mg (sin Θ) = µk (mg) (cos Θ) 
µk = tan Θ 
Θ = arctan(µk)
= arctan (0.35)
≈ 19.3°
 
        
             
        
        
        
Answer:
option 1 will be the answer.
Explanation:
hope it helps.
 
        
                    
             
        
        
        
Since my givens are x = .550m [Vsub0] = unknown
 [Asubx] = =9.80
 
 [Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0]
[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0]) 
Vsubx is the final velocity, which at the max height is 0, and Xsub0 is just 0 as that's where it starts so I just plug the rest in 
0^2 = [Vsub0x]^2 + 2[-9.80]*(.550) 
0 = [Vsub0x]^2 -10.78 
10.78 = [Vsub0x]^2 
Sqrt(10.78) = 3.28 m/s