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2 years ago

Adiabatic process is a process in which _ is constant (a) temperature (b)volume (c)pressure (d) heat

Chemistry

1 answer:

fomenos2 years ago

3 0

Answer: Adiabatic process is a process in which <u>heat</u> is constant

Explanation:

The processes in which temperature remains constant is called isothermal process.

The process in which Volume remains constant is called isochoric process.

The process in which pressure remains constant is called isobaric process.

The process in which no heat is gained or lost by the system, Hence heat remains constant is called as adiabatic process.

Thus option d) heat is correct

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Which of the following is the ground state electrons configuration of the F ion

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Explanation:

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2 years ago

Student added a strip of aluminium metal in aqueous copper(2)Sulfate but no reaction occured. Suggest a reason why.

kari74 [83]

Answer:

See Explanation

Explanation:

It is a common observation that a strip of aluminium metal in aqueous copper(II)Sulfate does not show any visible reaction. Aluminium is normally expected to displace copper in solution since it is higher than copper in the electrochemical series.

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2 years ago

Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.

Lilit [14]

The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element % Atomic mass Relative no. of atoms Simplest whole ratio

C 40.6 12 $\frac{40.6}{12}$ = 3.3 $\frac{3.3}{3.3} = 1$

H 5.1 1 $\frac{5.1}{1}$ = 5.1 $\frac{5.1}{3.1} = 2$

O 54.2 16 $\frac{54.2}{16}$ = 3.3 $\frac{3.3}{3.3} = 1$

The Empirical formula of compound is C₁H₂O₁ or CH₂O

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

$n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}$

$= \frac{118.084}{30}$

= 4

Molecular formula = n × Empirical formula

= 4 (C₁H₂O₁)

Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

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