19.60g of phosphoric acid is neutralized by 500g solution of sodium hydroxide.
2 answers:
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Answer:
The correct answer is: pH= 4.70
Explanation:
We use the <em>Henderson-Hasselbach equation</em> in order to calculate the pH of a buffer solution:
Given:
pKa= 4.90
[conjugate base]= 4.75 mol
[acid]= 7.50 mol
We calculate pH as follows:
pH = 4.90 + log (4.75 mol/7.50 mol) = 4.90 + (-0.20) = 4.70
<u>Answer:</u> The molarity of HCl solution is 0.262 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of HCl = 0.3366 g
Molar mass of HCl = 36.5 g/mol
Volume of the solution = 35.23 mL
Putting values in above equation, we get:
Hence, the molarity of HCl solution is 0.262 M.