Answer: F2 : bond order= 1.0
F2+: bond order = 1.5
F2- : bond order = 0.5
Explanation:
1. Starting with F2+
The configuration gives;
F2+ = 9F = 1S2.2S2.2P5
= 9F+ = 1S2.2S2.2P4 (this shows it gives out an electron)
Electronic configuration = σ 1S2σ*1S2σ2S2σ*2S2σ2Pz2 π2Px2 = π2Py2 π*2Px2 = π*2Py1
The number of Electrons = (9*2) – 1 = 18 -1 = 17
Bonding electrons (Nb) = 10
Antibonding electrons (Na) = 7
Bond order = (10-7)/2 = 3/2 = 1.5
Number of unpaired electrons = 1
2. Starting with F2
The configuration gives;
F2 = 9F = 1S2.2S2.2P5
9F = 1S2.2S2.2P5 (this shows no loss of an electron)
Electronic configuration = σ 1S2σ*1S2σ2S2σ*2S2σ2Pz2 π2Px2 = π2Py2 π*2Px2 = π*2Py2
The number of Electrons = (9*2) = 18 electrons
Bonding electrons (Nb) = 10
Antibonding electrons (Na) = 8
Bond order = (10-8)/2 = 2/2 = 1.0
Number of unpaired electrons = 0
3. Starting with F2-
The configuration gives;
F2- = 9F = 1S2.2S2.2P5
10F--= 1S2.2S2.2P6 (this shows an addition of an electron)
Electronic configuration = σ 1S2σ*1S2σ2S2σ*2S2σ2Pz2 π2Px2 = π2Py2 π*2Px2 = π*2Py2 σ*2Pz
The number of Electrons = (9*2) + 1 = 19 electrons
Bonding electrons (Nb) = 10
Antibonding electrons (Na) = 9
Bond order = (10-9)/2 = 1/2 = 0.5
Number of unpaired electrons = 1
To get the order of bond as well as length, we know that;
Bond order directly proportional to 1/ Bond length
Therefore the Ascending Bond length = F2+ ˂ F2 ˂ F2-
