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3 years ago

Alfred wegener l is best known for what hypothesis?

Chemistry

2 answers:

ozzi3 years ago

7 0

C- continental drift

Sphinxa [80]3 years ago

3 0

I would agree on C....

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Predict the products for the following chemical reaction: H2 + O2 →

RSB [31]

The answer is C I got it right so hope it helped ;)

6 0

3 years ago

The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +

Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is $1.1 \times 10^{-3} M$ .

(b) The solubility of CuCl in 0.1 M NaCl is $9.5 \times 10^{-3} M$ .

Explanation:

(a) Chemical equation for the given reaction in pure water is as follows.

$CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)$

Initial: 0 0

Change: +x +x

Equilibm: x x

$K_{sp} = 1.2 \times 10^{-6}$

And, equilibrium expression is as follows.

$K_{sp} = [Cu^{+}][Cl^{-}]$

$1.2 \times 10^{-6} = x \times x$

x = $1.1 \times 10^{-3} M$

Hence, the solubility of CuCl in pure water is $1.1 \times 10^{-3} M$ .

(b) When NaCl is 0.1 M,

$CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)$ , $K_{sp} = 1.2 \times 10^{-6}$

$Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq)$ , $K = 8.7 \times 10^{4}$

Net equation: $CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)$

$K' = K_{sp} \times K$

= 0.1044

So for, $CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)$

Initial: 0.1 0

Change: -x +x

Equilibm: 0.1 - x x

Now, the equilibrium expression is as follows.

K' = $\frac{CuCl_{2}}{Cl^{-}}$

0.1044 = $\frac{x}{0.1 - x}$

x = $9.5 \times 10^{-3} M$

Therefore, the solubility of CuCl in 0.1 M NaCl is $9.5 \times 10^{-3} M$ .

7 0

3 years ago

A balloon that has a volume of 9.45L of helium is released at the ground where the pressure is 760mmHg. What is the volume of th

max2010maxim [7]

Answer:

What is the volume of the balloon when it rises in the atmosphere to a place where pressure is 640mmHg

4 0

2 years ago

Which one of these samples contains the smallest number of molecule?

erma4kov [3.2K]

Answer:

E) 1.0L of He at STP

Explanation:

8 0

3 years ago

A sample of krypton gas with a volume of 10.00 L has a temp of 303 K and exerts

marshall27 [118]

Answer: The final volume will be 14.85 L.

Explanation:

To calculate the final volume when temperature increases, we use Charles' Law.

This law states that volume is directly proportional to the temperature of the gas if number of moles and pressure remains constant.

$V\propto T\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ = Initial volume and temperature

$V_2\text{ and }T_2$ = Final volume and temperature

We are given:

$V_1=10L\\
T_1=303K\\
V_2=?L\\
T_2=450K$

Putting values in above equation, we get:

$\frac{10L}{303K}=\frac{V_2}{450K}$

$V_2=14.85L$

Hence, the final volume of the gas is 14.85L

7 0

3 years ago