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Stolb23 [73]
3 years ago
6

A ball is initially moving with a velocity 0.5m/s. Its velocity decreases at a rate of 0.05m/s^2. How much time will it take to

stop? How much distance will the ball travel before it stops
Physics
1 answer:
gogolik [260]3 years ago
5 0

Answer:  t = 10 s , s = 2,5 m

Explanation:   (1) Speed v = v0 + at and (2) distance s = v0t + ½at².

Now  v0 = 0.5 m/s , v = 0 and a = -0.05 m/s²

Solve from equation (1)   t = -v0 / a = - 0.5 m/s / -0.05 m/s² =   10 s

Add t = 10 s to equation (2 )   s = 0.5 m/s · 10 s + 0.5· (-0.05 m/s²)· (10 s)²

= 5 m - 2,5 m = 2,5 m

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What type of equilibrium is guaranteed by each condition of equilibrium
Ostrovityanka [42]

Answer: Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium

Explanation: Hope this helped

5 0
3 years ago
Using your best estimates, how many times would you have to slap a 1 kg rotisserie chicken in order to cook it? You can assume t
FromTheMoon [43]

Answer:

n= 16021.03 slaps

Explanation:

Using law of Energy conservation

E_{thermal}= Kinetic energy of hand

⇒mc\Delta T= n\frac{1}{2}m_hv_h^2

m_h= mass of the hand = 0.4 kg

v_h= velocity of the hand = 10 m/s

n= number of slaps

c= 4180 J/Kg °C

m= mass of chicken = 1 kg

Assuming all the energy of hand goes into chicken

Given Ti=0°C and T_f= 170 F= 76.66°C

Now putting the values in above equation to get n

1\times4180(76.66)= n\frac{1}{2}0.4\times10^2

n= 16021.03 slaps

8 0
3 years ago
A spinning flywheel has rotational inertia I = 474.0 kg·m2. Its angular velocity decreases from 26.2 rad/s to zero in 204.0 s du
Flura [38]

Answer:

\tau = 60.88 N.m

Explanation:

given,

rotational inertia, I = 474.0 kg·m²

decrease in angular velocity

ω₁ = 26.2 rad/s        ω₂ = 0 rad/s

time = 204 s

torque = ?

\tau = I \alpha

\alpha = \dfrac{\omega_1-\omega_2}{t}

\alpha = \dfrac{26.2-0}{204}

   α = 0.128 rad/s²

\tau = I \alpha

\tau = 474\times 0.128

\tau = 60.88 N.m

frictional torque acting by the flywheel is equal to 60.88 N.m

7 0
3 years ago
Which is an electromagnetic wave A. The waves that heat a cup of water in a microwave oven B. A flag waving in the wind C. Turni
viva [34]

Answer:

The answer would be A. The waves that heat a cup of water in a microwave oven

7 0
3 years ago
F both the mass of the body and the force acting on it are doubled, then acceleration--------------------
Alekssandra [29.7K]

Answer:

d. remains same​

Explanation:

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Force = mass * acceleration

Acceleration = \frac {Force}{mass}

If both the mass of the body and the force acting on it are doubled, then acceleration remains the same​.

Given the following data;

Mass = 2Mass

Force = 2Force

Substituting into the formula, we have;

Acceleration = \frac {2Force}{2Mass}

Acceleration = \frac {Force}{Mass}

6 0
3 years ago
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