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Katen [24]
3 years ago
13

A rifle fires a 3.56 x 10-2-kg pellet straight upward, because the pellet rests on a compressed spring that is released when the

trigger is pulled. The spring has a negligible mass and is compressed by 6.61 x 10-2 m from its unstrained length. The pellet rises to a maximum height of 4.83 m above its position on the compressed spring. Ignoring air resistance, determine the spring constant.
Physics
1 answer:
vivado [14]3 years ago
5 0

Answer:

k = 773.64 N/m

Explanation:

Given:

mass of the pellet, m = 3.56 x 10² kg

Compression in spring, x = 6.61 × 10⁻² m

Height of rise of the pellet, h = 4.83 m

Now, let k be the spring constant

From the concept of conservation of energy, we get

gravitation potential energy acquired by the pellet will be from the energy provided by the spring

thus,

mgh = \frac{1}{2}kx^2

where, g is the acceleration due to the gravity

on substituting the values, we get

3.56\times10^2\times9.8\times4.83 = \frac{1}{2}k\times(6.61\times10^{-2})^2

or

1.685 = .002178 × k

k = 773.64 N/m

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7 0
3 years ago
A projectile is shot on level ground with a
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Answer:

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Can also use range formula

R = v^2 sin (2 theta) / g

tan theta = 34 / 17 = 2

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sin 126.9 = .8

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4 years ago
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Answer:

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8 0
3 years ago
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