Explanation:
(a) v = 2π r / t
v = 2π (0.85 m) / (0.65 s)
v = 8.2 m/s
(b) a = v² / r
a = (8.2 m/s)² / (0.85 m)
a = 79 m/s²
(c) F = ma
F = (0.013 kg) (79 m/s²)
F = 1.0 N
Answer:
A negatively charged particle -q is placed at the center of a uniformly charged ring, where the ring has a total positive charge Q as shown in the following figure. The particle, confined to move along the x axis, is moved a small distance x along the axis ( where x << a) and released. Show that the particle oscillates in simple harmonic motion with a frequency given by,
Every action has an equal opposite reaction
The force between two charges objects is related to separation.
