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3 years ago

Y = 3x^2+20 when x = 21

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

5 0

Answer:

y=1343

Step-by-step explanation:

when you plug in 21 for x the equation would be 3(21)^2+20 solve using the order of operations and you get 1343

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3 years ago

Find the slope of a line that passes through the points (17,2) and (17,-3)

Yuri [45]

Answer:

Undefined

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

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3 years ago

37 35 Х x = What’s the answer?

Ainat [17]

Answer:

Step-by-step explanation:

use Pythagorean theorem

37^2 = 35^2 + x^2

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3 years ago

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Use compatible numbers to estimate the quotient. 486/6

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4 years ago

Consider the initial value problem:

Inessa [10]

Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

3 0

4 years ago