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const2013 [10]
2 years ago
7

Identify the pair of angles shown in the figure.

Mathematics
1 answer:
Katen [24]2 years ago
7 0

Answer:

d

Step-by-step explanation:

i think

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Can you help me out? In a test
NikAS [45]

Answer:

B

Step-by-step explanation:

8 0
2 years ago
Divide. simplify your answer (2x^4-6x^3+4x^2-3x)*(2x)
lbvjy [14]

Answer:

x^3-3x^2+2x-\frac{3}{2}

Step-by-step explanation:

We can divide polynomials by other polynomials by dividing each term by the denominator. Remember, when we divide a variable by itself, we must change the exponent in our answer according to exponent rules.

\frac{ (2x^4-6x^3+4x^2-3x)}{2x}=\frac{2x^4}{2x} -\frac{6x^3}{2x} +\frac{4x^2}{2x} -\frac{3x}{2x} =x^3-3x^2+2x-\frac{3}{2}


4 0
3 years ago
Read 2 more answers
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
Evaluate: -8 over 9 + 4 over 9 - 2 over 9
stepan [7]
The answer is -2/3 from the solution above

4 0
3 years ago
Read 2 more answers
The number shown above belongs to which of the following subsets of the real numbers?
Nookie1986 [14]

Answer:

Rational

Step-by-step explanation:

the rational number subset contains fractions

3 0
3 years ago
Read 2 more answers
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