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hjlf
3 years ago
14

A rock is thrown horizontally off a cliff with an initial velocity of 15 m/s. How high was the cliff if the rock lands 22 m from

the base of the cliff?
Physics
2 answers:
Helen [10]3 years ago
3 0

Answer:

22 m

Explanation:

Hunter-Best [27]3 years ago
3 0

Answer:

cliff height = 10.55 m

Explanation:

Remarks

  • This is one of those questions that defies belief. The final vertical velocity is the same as if you just dropped the rock, which is amazing.
  • Another amazing fact is that the horizontal speed has no acceleration.
  • And  amazing fact number three is the the vertical initial speed is 0.
  • And finally, the time taken to go horizontally = time to go vertically.

Solution

<u>Time</u>

So the time taken is d = r * t  

Remember, this formula can only be used when there is no acceleration.

d = 22 meters

r = 15 m/s

t = ?

t = d / r

t = 22 / 15

t = 1.467

<u>Height of the Cliff</u>

vi = 0 (vertially)

a = 9.8 m/s^2

t = 1.467 seconds    The time horizontally and vertically is the same.

d = ?

<u>Formula</u>

d = vi*t + 1/2 a t^2

<u>Solution</u>

d = 0 + 1/2 * 9.8 * 1.467^2

d = 10.55 meters.

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Explanation:What is centripetal acceleration?

Can an object accelerate if it's moving with constant speed? Yup! Many people find this counter-intuitive at first because they forget that changes in the direction of motion of an object—even if the object is maintaining a constant speed—still count as acceleration.

Acceleration is a change in velocity, either in its magnitude—i.e., speed—or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the speed might be constant. You experience this acceleration yourself when you turn a corner in your car—if you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion. What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we'll examine the direction and magnitude of that acceleration.

The figure below shows an object moving in a circular path at constant speed. The direction of the instantaneous velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation—the center of the circular path. This direction is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration

a

c

a

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a, start subscript, c, end subscript; centripetal means “toward the center” or “center seeking”.

5 0
4 years ago
Laasya accurately explains to Clark the role of decomposers in an ecosystem. Choose the sentences that she should include in her
Brrunno [24]

The Sentences which should Include in Laasya Explanation are :

B. Decomposers breakdown Dead Organisms.

D. Decomposers help to recycle Nutrients in an Ecosystem.

<u>Because </u>:

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✿ Ecosystems cannot function without Decomposers.

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An object at rest increases its velocity to 10 m/s in 3 seconds. what is its acceleration?
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4 years ago
A light body and a heavy body have the
Elena-2011 [213]

Answer:

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Pretty sure this is correct

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7 0
3 years ago
Read 2 more answers
While standing at the top of an 100 m high observatory, you accidentally dropped your phone through the grates (it is now fallin
Arturiano [62]

Using the idea of motion under gravity, it will take 0.5 seconds more before the phone hits the ground.

<h3>What is the distance covered?</h3>

The distance covered is obtained form the equations of kinematics under gravity.

Now;

v = u + gt

Recall that it was dropped from a height hence u = 0 m/s

v = gt

v = 9.8 m/s^2 * 4 s

v = 39.2 m/s

Now;

h = ut + 1/2gt^2

but u = 0 m/s

h = 1/2gt^2

h = 1/2 * 9.8 * (4)^2

h = 78.4 m

The phone  will not hit the ground within this time

For the phone to hit the ground;

h = 1/2gt^2

if h = 100 m

100 = 1/2 * 9.8 * t^2

2 * 100/9.8 =  t^2

t = √2 * 100/9.8

t = 4.5 seconds

It will take about 0.5 seconds more before the phone will hit the ground.

Learn more about motion under gravity:brainly.com/question/15120445

#SPJ1

3 0
2 years ago
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