A force of 4.97 n acts on a(n) 4.9 kg object for 20.6 s. what is the object's change in momentum? answer in units of n

At a certain instant, the speedometer of the car indicates 80 km/h.

Scorpion4ik [409]

Answer:

It tells the speed of car. At this time the speed of car is 80km/h , means if the car runs constantly at this speed then it will cover 80 kilometres in 1 hour.

. 

.

${\bold{\red{HOPE\:IT\:HELPS!}}}$

$\color{yellow}\boxed{\colorbox{black}{MARK\: BRAINLIEST!❤}}$

4 0

2 years ago

What is the kinetic theory of matter? How does it relate to the motion of molecules?

Charra [1.4K]

Answer:

Explanation:

Kinetic energy is energy that an object has because of its motion. The Kinetic Molecular Theory explains the forces between molecules and the energy that they possess. This theory is based on three theories about matter. Matter is composed of small particles (atoms, molecules, and ions).

7 0

3 years ago

On a horizontal frictionless surface, a small block with mass 0.200 kg has a collision with a block of mass 0.400 kg. Immediatel

Akimi4 [234]

Answer:48.2 Joules

Explanation:

Given

two masses of 0.2 kg and 0.4 kg collide with each other

after collision 0.2 kg deflect 30 north of east and 0.4 kg deflects 53.1 south of east

Velocity of 0.2 kg mass is

$v_{0.2}=12\cos (30)\hat{i}+12\sin (30)\hat{j}$

$|v_{0.2}|=11.99 m/s\approx 12 m/s$

Velocity of 0.4 kg mass

$v_{0.4}=13\cos (53.1)\hat{i}-12\sin (53.1)\hat{j}$

$|v_{0.4}|=12.99 m/s\approx 13 m/s$

Thus total Kinetic energy $=\frac{0.2\times 12^2}{2}+\frac{0.4\times 13^2}{2}$

Kinetic energy=48.2 J

8 0

3 years ago

You pull on a spring whose spring constant is 22 N/m, and stretch it from its equilibrium length of 0.3 m to a length of 0.7 m.

Liono4ka [1.6K]

Answer:

W= 4.4 J

Explanation

Elastic potential energy theory

If we have a spring of constant K to which a force F that produces a Δx deformation is applied, we apply Hooke's law:

F=K*x Formula (1): The force F applied to the spring is proportional to the deformation x of the spring.

As the force is variable to calculate the work we define an average force

$F_{a} =\frac{F_{f}+F_{i} }{2}$ Formula (2)

Ff: final force

Fi: initial force

The work done on the spring is :

W = Fa*Δx

Fa : average force

Δx : displacement

$W = F_{a} (x_{f} -x_{i} )$ :Formula (3)

$x_{f}$ : final deformation

$x_{i}$ :initial deformation

Problem development

We calculate Ff and Fi , applying formula (1) :

$F_{f} = K*x_{f} =22\frac{N}{m} *0.7m =15.4N$

$F_{i} = K*x_{i} =22\frac{N}{m} *0.3m =6.6N$

We calculate average force applying formula (2):

$F_{a} =\frac{15.4N+6.2N}{2} = 11 N$

We calculate the work done on the spring applying formula (3) : :

W= 11N*(0.7m-0.3m) = 11N*0.4m=4.4 N*m = 4.4 Joule = 4.4 J

Work done in stages

Work is the change of elastic potential energy (ΔEp)

W=ΔEp

ΔEp= Epf-Epi

Epf= final potential energy

Epi=initial potential energy

$E_{pf} =\frac{1}{2} *k*x_{f}^{2}$

$E_{pi} =\frac{1}{2} *k*x_{i}^{2}$

$E_{pf} =\frac{1}{2} *22*0.7^{2} = 5.39 J$

$E_{pf} =\frac{1}{2} *22*0.3^{2} = 0.99 J$

W=ΔEp= 5.39 J-0.99 J = 4.4J

:

4 0

3 years ago

Research has shown that the electrons orbit the nucleus in circular motions as shown on the classic Bohr model.

Stels [109]

Research has shown that the electrons orbit the nucleus in circular motions as shown on the classic Bohr model. FALSE

6 0

3 years ago

Read 2 more answers

A force of 4.97 n acts on a(n) 4.9 kg object for 20.6 s. what is the object's change in momentum? answer in units of n · s.