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3 years ago

5

so i need help on my test, i would put the link here but it does not let me so i´ll just put the link down below i need the answ

ers by 10:51 thank you plzz

2 answers:

a_sh-v [17]3 years ago

5 0

Answer: I don't see the link

Explanation:

dedylja [7]3 years ago

3 0

Answer:

m

Explanation:

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Explanation:

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3 years ago

Write the molecular formula of sodium bicarbonate and write any two uses of it.

gulaghasi [49]

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3 years ago

At this pressure, how many molecules of air would there be in a 20 ∘C experimental chamber with a volume of 0.020 m3 ?

jonny [76]

Answer:

Explanation: The lowest pressure in a laboratory is 4.0×10^-11Pa

Using Ideal gas equation

PV = nRT

P= 4.0×10^-11Pa

V= 0.020m^3

T= 20+273= 293k

n=number of moles = m/A

Where m is the number of molecules and A is the Avogradro's number=6.02×10²³/mol

R=8.314J/(mol × K)

PV= m/A(RT)

4.0×10^-11 ×0.020 = m/6.02×10²³(8.314×293)

m = 4.0×10^-11×0.020×6.02×10^23 / (8.314×293)

m = 1.98×10^8 molecules

Therefore,the number of molecules is 1.98×10^8

8 0

3 years ago

In general the human ear is most sensitive to sounds at 2500 hz. Assuming that sound moves at 330m/s what is the wavelength of s

elena-s [515]

Answer:

0.132 meters is the wavelength of sounds to which people are most sensitive.

Explanation:

Frequency of the sound human ears are most sensitive to = $\nu = 2500Hz=2500 s^{-1}$

Speed of the sound wave = S = 330 m/s

Wavelength of the sound human ears are most sensitive to = $\lambda = ?$

$\nu=\frac{S}{\lambda }$

$2500 s^{-1}=\frac{330 m/s}{\lambda }$

$\lambda =\frac{330 m/s}{2500 s^{-1}}=0.132 m$

0.132 meters is the wavelength of sounds to which people are most sensitive.

3 0

3 years ago

A potential energy diagram is shown. A graph is plotted with Potential Energy in KJ on the y axis and Reaction Pathway on the x

Leya [2.2K]

Answer:

NOT A

Explanation:

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4 years ago