Hey there!
Magnesium chlorate: Mg(ClO₃)₂
Find molar mass.
Mg: 1 x 24.305 = 24.305
Cl: 2 x 35.453 = 70.906
O: 6 x 16 = 96
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191.211 g/mol
We have 187.54 grams.
187.54 ÷ 191.211 = 0.9808
There are 0.9808 moles in 187.54 grams of magnesium chlorate.
Hope this helps!
Answer:
if you did it would probably make it bigger...
Explanation:
:)
Answer:
The answer is "
"
Explanation:
Given:
Molarity= number of moles
because it is 1 Liter
therefore,
it takes 20 mL of Tris.
So, take 
Answer:
if an atom gains an electron, the ion has negetive charge
Answer:
1. 0.125 mole
2. 42.5 g
3. 0.61 mole
Explanation:
1. Determination of the number of mole of NaOH.
Mass of NaOH = 5 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass /molar mass
Mole of NaOH = 5/40
Mole NaOH = 0.125 mole
2. Determination of the mass of NH₃.
Mole of NH₃ = 2.5 moles
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 2.5 × 17
Mass of NH₃ = 42.5 g
3. Determination of the number of mole of Ca(NO₃)₂.
Mass of Ca(NO₃)₂ = 100 g
Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]
= 40 + 2[14 + 48]
= 40 + 2[62]
= 40 + 124
= 164 g/mol
Mole of Ca(NO₃)₂ =?
Mole = mass /molar mass
Mole of Ca(NO₃)₂ = 100 / 164
Mole of Ca(NO₃)₂ = 0.61 mole
