All categories

2 years ago

A sample of 0.200 moles of nitrogen occupies 0.400 L. Under the same conditions, what number of moles occupies 1.200 L

Chemistry

1 answer:

IRISSAK [1]2 years ago

7 0

The number of mole of nitrogen that occupies 1.2 L under the same condition is 0.6 mole

<h3>Data obtained from the question </h3>

Initial mole (n₁) = 0.2 mole
Initial volume (V₁) = 0.4 L
Final volume (V₂) = 1.2 L
Final mole (n₂) =?

<h3>How to determine the final mole </h3>

The final mole can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side n

PV / n = RT

Divide both side by P

V / n = RT / P

RT / P = constant

V / n = constant

Thus,

V₁ / n₁ = V₂ / n₂

0.4 / 0.2 = 1.2 / n₂

2 = 1.2 / n₂

Cross multiply

2 × n₂ = 1.2

Divide both side by 2

n₂ = 1.2 / 2

n₂ = 0.6 mole

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ1

You might be interested in

Round to 4 significant figures.<br> 35.5450

Lelu [443]

Answer:
35.5450 will be rounded to 35.55
Explanation:
=35.5450
if the last digit is less than 5 then it will be ignored
=35.545
when the dropping digit is 5 then the retaining digit will increse by a factor of 1
=35.55
i hope this will help you

3 0

3 years ago

Read 2 more answers

All molecular motion stops at 0 on this scale

Oxana [17]

Kelvin Hope this helps

4 0

3 years ago

Read 2 more answers

Which event must always occur for a chemical reaction to occur

Lorico [155]

There must be effective collisions between the reacting chemical particles in order for the chemical reaction to occur.

8 0

2 years ago

Which two compounds are classified as bases by the Brønsted-Lowry definition, but not by the Arrhenius definition, and why?

konstantin123 [22]

Answer: Ammonia (NH3) and sodium carbonate (Na2CO3), because they accept hydrogen ions but lack hydroxide ions.

Explanation:

i took the test and got it correct :) hope this helps

6 0

3 years ago

The enthalpy of vaporization of Bromine is 15.4 kJ/mol. What is the energy change when 80.2 g of Br2 condenses to a liquid at 59

Aleksandr-060686 [28]

The enthalpy of vaporization of Bromine is 15.4 kJ/mol. -7.7 kJ is the energy change when 80.2 g of Br₂ condenses to a liquid at 59.5°C.

<h3>What is Enthalpy of Vaporization ?</h3>

The amount of enthalpy or energy that must be added to a liquid substance into gas substance is called Enthalpy of Vaporization. It is also known as Latent heat of vaporization.

<h3>How to find the energy change from enthalpy of vaporization ?</h3>

To calculate the energy use this expression:

$Q = n \Delta H_{\text{vapo.}$

where,

Q = Energy change

n = number of moles

$\Delta H_{\text{Vapo.}}$ = Molar enthalpy of vaporization

Now find the number of moles

Number of moles (n) = $\frac{\text{Given Mass}}{\text{Molar mass}}$

= $\frac{80.2\ g }{159.8\ g/mol}$

= 0.5 mol

Now put the values in above formula we get

$Q = - n \Delta H_{\text{vapo.}$ [Negative sign is used because Br₂ condensed here]

= - (0.5 mol × 15.4 kJ/mol)

= - 7.7 kJ

Thus from the above conclusion we can say that The enthalpy of vaporization of Bromine is 15.4 kJ/mol. -7.7 kJ is the energy change when 80.2 g of Br₂ condenses to a liquid at 59.5°C.

Learn more about the Enthalpy of Vaporization here: brainly.com/question/13776849

#SPJ1

8 0

1 year ago