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2 years ago

How much power does it take to lift 70.0 N to 5.0 m high in 5.00 s?

Physics

1 answer:

lesantik [10]2 years ago

3 0

Answer:

Power = 70 W

Explanation:

Given that,

Force, F = 70 N

Height, h = 5 m

Time, t = 5 s

We need to find the power of the object. We know that,

Power = work done/time

Put all the values,

$P=\dfrac{Fd}{t}\\\\P=\dfrac{70\times 5}{5}\\\\P=70\ W$

So, the required power is 70 W.

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A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I

Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

$E=-\dfrac{d\phi}{dt}$

$E=-B\dfrac{dA}{dt}$

$E=-B\dfrac{A_{2}-A_{1}}{dt}$

$E=B\dfrac{A_{1}-A_{2}}{dt}$ .....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

$l=2\times 2\pi\times r_{1}$

$l=2\times 2\pi\times 0.63$

$l=7.916\ m$

The length when wire is in one loop

$l=2\pi\times r_{2}$

$7.916=2\times \pi\times r_{2}$

$r_{2}=\dfrac{7.916}{2\times \pi}$

$r_{2}=1.259\ m$

We need to calculate the initial area

$A_{1}=N\times\pi\times r_{1}^2$

Put the value into the formula

$A_{1}=2\times3.14\times(0.63)^2$

$A_{1}=2.49\ m^2$

The final area is

$A_{2}=N\times\pi\times r_{2}^2$

$A_{2}=1\times\pi\times(1.259)^2$

$A_{2}=4.98\ m^2$

Put the value of initial area and final area in the equation (I)

$E=0.219\dfrac{2.49-4.98}{0.0572}$

$E=-9.533\ V$

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0

3 years ago

A 500-kilogram sports car accelerates uniformly from rest, reaching a speed of 30 meters per second in 6 seconds. During the 6 s

AlekseyPX

Answer:

90 m

Explanation:

Given that

Mass of the car, m = 500 kg

Initial speed of the car, u = 0 m/s

Final speed of the car, v = 30 m/s

Time taken to travel, t = 6 s

average speed v = (30 + 0) / 2 = 15

We are going to be using the most very basic equations to solve this.

speed can be defined as the ratio of distance with respect to time.

v = d/t, Where

v = speed.

d = distance travelled and

t = time taken

if we invert this, we can get that

d = v.t

distance is multiplication of speed and time. We will be using the average speed we calculated above, so

Distance travelled in 6 s,

d = 15 * 6

d = 90 m.

therefore, the distance travelled by the car in this 6 s is 90 m

4 0

3 years ago

What is physical quantity

Brums [2.3K]

A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit.

5 0

3 years ago

Read 2 more answers

A particle moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.

mrs_skeptik [129]

The particle's acceleration is 5.1 m/s²

<h3>What is Acceleration ?</h3>

Acceleration can be defined as the rate at which velocity is changing. It is a vector quantity and it is measured in m/s²

Given that a particle is moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.72 m/s at t=5.59s

The given parameters are;

V1 = 2.35 m/s

V2 = - 8.72 m/s

T1 = 3.42s

T2 = 5.59s

Acceleration a = ΔV ÷ ΔT

a = (2.35 + 8.72) / (5.59 - 3.42)

a = 11.07 / 2.17

a = 5.1 m/s²

Therefore, the particle's acceleration is 5.1 m/s²

Learn more about Acceleration here: brainly.com/question/9069726

#SPJ1

4 0

1 year ago

A screw having 50% efficiency is driven by a rod and 25 cm. The pitch of the screw is 1/10cm Calculate velocity ratio and mechan

neonofarm [45]

(a) The velocity ratio of the screw is 1570.8.

(b) The mechanical advantage of the screw is 785.39.

<h3>Velocity ratio of the screw</h3>

The velocity ratio of the screw is calculated as follows;

V.R = 2πr/P

where;

P is the pitch = 1/10 cm = 0.1 cm = 0.001 m
r is radius = 25 cm = 0.25 m

V.R = (2π x 0.25)/(0.001)

V.R = 1570.8

<h3>Mechanical advantage of the screw</h3>

E = MA/VR x 100%

0.5 = MA/1570.8

MA = 785.39

Learn more about mechanical advantage here: brainly.com/question/18345299

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4 0

2 years ago