2 years ago

How much power does it take to lift 70.0 N to 5.0 m high in 5.00 s?

Physics

1 answer:

lesantik [10]2 years ago

3 0

Answer:

Power = 70 W

Explanation:

Given that,

Force, F = 70 N

Height, h = 5 m

Time, t = 5 s

We need to find the power of the object. We know that,

Power = work done/time

Put all the values,

$P=\dfrac{Fd}{t}\\\\P=\dfrac{70\times 5}{5}\\\\P=70\ W$

So, the required power is 70 W.

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