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Annette [7]
3 years ago
14

PLEASE HELP ME IF YOU KNOW STUFF ABOUT ENERGY TYSM

Physics
2 answers:
muminat3 years ago
7 0
Answer:
1. Kinetic
2. Joules
3. Temperature

Explanation: I think this is right.
Tomtit [17]3 years ago
5 0

Answer:

  1. Kinetic Energy
  2. Potential energy
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What is the momentum of a 72 kg baseball player who slides into home plate
Alina [70]

Answer:

B) 350 kg m/s

Explanation:

momentum or p is given by the equation p= mxv

We have the mass and velocity so we can use the equation directly

p= 72kg x 4.9 m/s

p= 352.8 kg m/s

4 0
3 years ago
Calculate the speed for a car that went a distance of 125 kilometers in 2 hours time.
Murljashka [212]
S=125km
t=2h
v=s/t=125/2=62,5km/h
or 62,5/3,6=17,36m/s
7 0
3 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl
aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i:  unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R=  131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2}  }

D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2}  }

D₂= 167.21 cm

Direction of the second displacement

\beta = tan^{-1} \frac{D_{y}}{D_{x} }

\beta = tan^{-1} \frac{62.18}{155.22 }

β= 21.8°

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

6 0
3 years ago
You walk towards Starbucks southward for 14 meters and then west for 9 meters. The trip takes you 3 minutes to walk there. What
zimovet [89]

Although you walked (14+9)= 23 meters of distance, you ended up only 16.64 meters from where you started. That's your "displacement".

Velocity = (displacement / (time)

Velocity = (16.64m)/(180s)

Velocity = 0.0925 m/s roughly Southwest.

(That's about 3.6 INCHES per second. Apparently, you really NEED that mocha java and it's associated drug.)

8 0
3 years ago
Neil Armstrong, the first human being to step on the moon, left a foot print that is essentially unchanged nearly 50 years later
Likurg_2 [28]

Since the boot-print was left there nearly 50 years ago, there has been very little wind and very little rain in that area, and plus, there have been very few people or other animals walking around in that spot to disturb it.

6 0
3 years ago
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