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luda_lava [24]
3 years ago
14

PLZ HELP, NO MESSING AROUND, WILL GIVE BRAINLIEST!

Chemistry
1 answer:
Vesnalui [34]3 years ago
3 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h2>Covalent Bond:</h2>

Covalent bond is a type of chemical bond which is due to the sharing an electron from each and every atom that is participating in the bond.

<h2>Ionic Bond:</h2>

Ionic bond is a type of bond which is formed due to the complete donation of an electron from one atom to another.

Ionic bond is formed between metals and non-metals. The group which provide the Metal are IA and IIA i.e. S block elements. The group which mostly provide non-metal is VII A i.e. halogens. The Metals give up their ONLY Valance shell electron which is accepted by the Non-metal. This results in formation of ions, The Metals gets the positive charge thus called cation and The non-metal gets a negative charge thus called anion. These Positive and Negative ion attract each other resulting in the formation of IONIC BOND.

<h2>_____________________________________</h2>

The Ionic bond is formed between The metal and non metal because, the metals have low ionization energy due to which the valence shell is ejected out easily, and The Non-Metals have high electron affinity which means that  they attract an electron with greater force because they need one electron to complete their octet. As the non metal has high electron affinity and metal have low electron affinity thus the electronegativity difference between the non metal and metal is more than 2 thus they make ionic bond.

<h2>_____________________________________</h2><h2>Rule of Electronegativity:</h2>

Electronegativity is the tendency of an atom to attract shared pair of electron. If there is electronegativity difference between the two atom more than 2 then it makes IONIC BOND. If the electronegativity difference is less than 2, it makes COVALENT BOND.

<h2>_____________________________________</h2><h2>Question:</h2>

The question says, the KCl has ionic bond but HCl has covalent bond, why?

<h2>Answer:</h2>

Answer is that KCl has electronegativity difference between K and Cl atom more than 2 thus it forms ionic bond. H and Cl has electronegativity difference of less than 2 thus it makes Covalent Bond. K donates its valence electron completely to the Chlorine atom because chlorine has much more electronegativity than potassium(K). H shares an electron with chlorine, it is not completely donated. H has pair of electron for sometime and chlorine has pair of electron for sometime, It is because the Chlorine and Hydrogen has less difference of electronegativity so they attract with almost same electronegativity.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

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Answer:

A Type of Drink

Explanation:

A controlled variable remains constant throughout the experiment.

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Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.
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Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

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