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3 years ago

Glacial striations have been found in South America, South Africa, India, and Australia. What do these marks tell scientist?

2 answers:

7 0

These mars can tell the scientist that there are still a lot of things that they can not discover. The glaciation can also tell us about the alignment of the earth and not just it can tell us about the climate. That is why it is really important for the scientist to study keenly in this kind of matters.

zalisa [80]3 years ago

3 0

that it use to be colder in that area

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Nitrogen and hydrogen react to produce ammonia.

Doss [256]

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2 years ago

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

2 years ago

180m/173 Tl -> 180/173 Tl + ? Express your answer as a nuclear equation

Law Incorporation [45]

Answer: The nuclear equation is $^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma$ .

Explanation:

A nuclear reaction in which a heavy particle splits into another particle along with release of energy is called a nuclear fission reaction.

For example, $^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma$

Here, energy is radiated in the form of gamma radiation.

Thus, we can conclude that the nuclear equation is $^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma$ .

4 0

2 years ago

Ductile means...

balu736 [363]

Answer:

Explanation:

3 0

2 years ago

What is the independent variable for a dry ice experiment

mote1985 [20]

The independent variable is a variable that is being manipulated or controlled. This is to see how it affects, changes and yields the outcome of the particular stimuli.

The dry ice experiment has an IV of temperature and a DV of melting time.

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3 years ago