See that remainder in the lower, right hand corner of this array? It's 2. That is the value of f(-2).
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
Answer:
the answer is 81,592 cuz you have to multiple
Answer:
Step-by-step explanation:
The discriminant is part of the quadratic formula. If the value of the discriminant is less than 0, you have 2 imaginary solutions; if the discriminant is equal to 0, you have 1 real solution; if the discriminant is greater than 0, you have 2 real solutions.
The discriminant is 
, which for us, looks like this:
which simplifies to -63. That means that the solutions are imaginary...not real at all. So in answer to your question, there are no real zeros at all.
Answer:
B.) 1/15
Step-by-step explanation:
- 10 total marbles
- 3/10 - 1/1 = 2/9
- 3/10 × 2/9 = 1/15
