Answer:
Deposition
Explanation:
It’s breaking down the rock :]
We can predict formula of ionic compounds by:
- Take a look at where the elements are listed on the periodic table.
- The amount of electrons that an element would need to gain or lose in order to resemble an atom of a nearby noble gas is one of the similarities that atoms in the same column as one another (group) tend to display.
- Alkali metal group I ions have +1 charges.
- Alkaline earth metals (group 2 ions) have a +2 charge.
- Nonmetal group 6 ions have a charge of -2.
- Halides in group 7 have a -1 charge.
- The charges of the transition metals cannot be predicted in a straightforward manner.
- Check out a table of charges (valences) to see potential values. The +1, +2, and +3 charges are most frequently employed in beginning and general chemistry courses.
- Keep in mind that the positive ion is always stated first when writing an ionic compound's formula.
These are the few guidelines we can use to product formula.
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Answer: 2. I see two colours in the test tube, white and grey at the bottom.
The density of water is a physical property.
You can measure it without changing the water to a different substance.
It is <em>not a physical change</em> because the water does not change to ice or steam.
You can observe a <em>chemical property</em> or a <em>chemical change</em> only if the water <em>changes to a different substance</em>.
Answer:
-) 2-methylbut-2-ene
-) 2-methylbut-1-ene
-) 3-methylbut-1-ene
Explanation:
in this case, the hydration of alkenes is a <u>marknovnikov reaction</u>, this means that the "OH" group would be added in the <u>most substituted carbon</u> of the double bond. (Figure 1)
For 2-methylbut-2-ene the most substituted carbon is the <u>tertiary carbon</u> (the carbon in the right of the double bond), so we will obtain the desired molecule. In 2-methylbut-1-ene the most substituted carbon is again the <u>tertiary carbon</u> (the carbon in the bottom of the double bond), so we will obtain 2-methyl-2-butanol. Finally, for 3-methylbut-1-ene the carbocation would be formed on carbon 3, this is a secondary carbocation. We can obtain a most stable carbocation if we do a <u>hydride shift</u> (Figure 2). With this new molecule is possible to obtain 3-methylbut-1-ene.