Free fall differs from terminal velocity, in that during free fall
1 answer:
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At that point it is no longer trying to uncompress nor is it trying to stretch. This is the same thing as a pendulum at the bottom of its swing, no longer falling but not yet rising against gravity. Thus the kinetic energy there is the same as the potential energy when it is compressed. The energy of compression is
This gives E=0.5(37)(0.2)²=0.74J
This is the same as the kinetic energy when it is at natural length
This gives E=0.5(37)(0.2)²=0.74J
This is the same as the kinetic energy when it is at natural length
Answer:
p = 8N/mm2
Explanation:
given data ;
diameter of cylinder = 150 mm
thickness of cylinder = 6 mm
maximum shear stress = 25 MPa
we know that
hoop stress is given as =
axial stress is given as =
maximum shear stress = (hoop stress - axial stress)/2
putting both stress value to get required pressure
t = 6 mm
d = 150 mm
therefore we have pressure
p = 8N/mm2