Answer:
effective dose is 1.2 mrem
Explanation:
given data
mass m = 70 kg
absorb n = 4.5 × 
energy = 1.2 MeV
neutrons = 10
to find out
equivalent dosage
solution
we know here total energy in a day is
total energy = 4.5 × × 1.2
total energy = 5.4 × 
eV
and total energy = 5.4 × × 1.6 × 
so total energy = 8.64 × 
J
and for mass 70 kg
it will be = 8.64 × / 70
= 1.23 × 
rad
so
effective dose is here = 1.23 × × 10 = 0.0012 rem
so effective dose is 1.2 mrem
Answer:
a)mass = 300kg
b) no of atoms = 1.81 x 10^26atoms.
c)Fission Activity = 207Bq
d) no of fissions = 1.79 × 107 d^-1
Explanation:
a)mass= (3×10-4)(10^6kg) = 300kg
b) no of atoms = (300kg) X (6.022×10^23/kg) = 1.81 x 10^26atoms.
c)Fission Activity = (0.69)(300kg) = 207Bq
d) no of fissions = (207)(86400) = 1.79 × 107 d^-1
Answer:
You can determine if the ship is moving by lying down and measuring your height.
Explanation:
Answer:
0.546 ohm / μm
Explanation:
Given that :
N = 1.015 * 10^17
Electron mobility, u = 3900
Hole mobility, h = 1900
Ng = 4.42 x10^22
q = 1.6*10^-19
Resistivity = 1/qNu
Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)
= 0.01578880889 ohm /cm
Resistivity of germanium :
R = 1 / 2q * sqrt(Ng) * sqrt(u*h)
R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)
R = 1 /0.0001831
R = 5461.4964 ohm /cm
5461.4964 / 10000
0.546 ohm / μm
<span>Radiometric dating or radioactive dating is a technique used to date materials such as rocks or carbon, in which trace radioactive mistakes were selected when they were formed.</span>
