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beks73 [17]
3 years ago
10

PLEASE HELP!! VERY URGENT.. DUE TODAY!! WILL MARK BRAINLIEST!! 25 points!

Mathematics
2 answers:
Elan Coil [88]3 years ago
7 0

Answer: If evaluating it’s -18f+6g

Step-by-step explanation:

anastassius [24]3 years ago
5 0

Answer:

-24

Step-by-step explanation:

f(3)=-2

g(-1)=6

Okay so to find out how to locate these answers, you plug in the x-value as the number inside, so for f(3), you're trying to find out what the y-value is at x=3 which would be -2.

Then, with these values, you can just solve using PEMDAS.

-6*f(3)-6*g(-1)=_

-6*-2-6*6_

12-36=-24

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Step-by-step explanation:

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If sin(x) = 0 and cos(x) = 1, what is cot(x)?
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Read 2 more answers
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

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u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

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8 0
3 years ago
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