<span>let the fsh jump with initial velocity (u) in direction (angle p) with horizontal
it can cross and reach top of trajectory if its top height h = 1.5m
and horizontal distance d = (1/2) Range
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let t be top height time
at top height, vertical component of its velocity =0
vy = 0 = u sin p - gt
t = u sin p/g
h = [u sin p]*t - 0.5 g[t[^2
1.5 = u^2 sin^2 p/g - u^2 sin^2 p/2g
u^2 sin^2 p/2g = 1.5
u^2 sin^2 p = 1.5*2*9.8 = 29.4
u sin p = 5.42 m/s >>>>>>>>>>>>>>> V-component
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t = HALF the time of flight
d = (1/2) Range (R) = (1/2) [2 u^2 sin p cos p/g]
1 = u^2 sin p cos p/g
u sin p * u cos p = 9.8
5.42 * u cos p = 9.8
u cos p = 1.81 m/s >>>>>>>>>>>>> H-component
check>>
u = sqrt[u^2 cos^2 p + u^2 sin^2 p] = 5.71 m/s
u < less than fish's potential jump speed 6.26 m/s
so it will able to cross</span>
Answer:
The magnetic field in the System is 0.095T
Explanation:
To solve the exercise it is necessary to use the concepts related to Faraday's Law, magnetic flux and ohm's law.
By Faraday's law we know that
Where,
electromotive force
N = Number of loops
B = Magnetic field
A = Area
t= Time
For Ohm's law we now that,
V = IR
Where,
I = Current
R = Resistance
V = Voltage (Same that the electromotive force at this case)
In this system we have that the resistance in series of coil and charge measuring device is given by,
And that the current can be expressed as function of charge and time, then
Equation Faraday's law and Ohm's law we have,
Re-arrange for Magnetic Field B, we have
Our values are given as,
Replacing,
Therefore the magnetic field in the System is 0.095T
The answer is Rh = 135 cm^3 and B = 0.05185 wh/m^2
Explanation:
Resitivity of silicon = 0.1
thickness = 100um
so, I = ma
Required to find out concentration of electron , we know that
Rh = up
By putting in the values,
Rh = 1350 x 0.1
Rh = 135 cm^3
Now consider,
Rh = 1 / Rh.q
= 1 / Rh . q
= 1 / 135 x1.609 x10^-19
= 4.6037 x 10^16 / cm^3
Vh = BIRh / w
B = Vh w/ IRh
B = -70 x10^-6 x 100 x10^-6 / 1x 10^-3 x 135 x 10^-6
B = 0.05185 wh / m^2
Charge= Protons- electrons
Charge= 35p-37e= -2
This Ion will have a charge of -2<span>. </span>
