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IceJOKER [234]
1 year ago
7

5. the combustion of a single molecule of methane produces about 10 ev of energy. a methane molecule has a mass of 16 amu. the f

ission of a uranium-235 atom
produces about 189 mev of energy. based on these numbers, about what mass of methane will produce as much energy as a single gram of uranium-235? (one mel
is equal to one million ev.)
oa 19 grams of methane
ob 304 grams of methane.
o c. 71.4 kilograms of methane
od 1,287 kilograms of methane
Physics
1 answer:
Alchen [17]1 year ago
7 0

The mass of methane will produce as much energy as a single gram of uranium-235 1,287 kilograms of methane. Option D is correct.

<h3>What is uranium?</h3>

Uranium, with the atomic number 92 and the symbol U in the periodic table, is a weakly radioactive element. One of the heavy metals that may be used as a concentrated energy source is uranium.

Given data;

⇒One mole of U-235 = 235 grams

=> 1 gram of U-235 = 1/235 moles

⇒1 mole of U-235 = 6.023 x 10²³ atoms

The no of atoms is;

=> 1/235 moles of U-235

⇒N = 6.023 x 10²³/235 atoms

⇒N=25.6 x 10²⁰ atoms

If one atom of U-235 gives is 189 x 10⁶ eV energy,25.6 x 10²⁰ atoms of U-235 gives;

=> 25.6 x 10²⁰ atoms of U-235 gives;

E = 25.6 x 10²⁰ x 189 x 10⁶

E= 4.8 x 10²⁹ eV energy

One methane molecule produces;

E = 10 eV of energy

=> To produce 4.8 x 10²⁹ eV energy, no. of molecules required;

= 4.8 x 10²⁸

6.032 x 10²³ molecules of methane = 16 gms

=> 4.8 x 10²⁸ molecules of methane = 16 x 4.8 x 10²⁸/ 6.032 x 10²³ gms

m= 12.75 x 10⁵ gms

m= 1275 kilograms of methane

m≅ 1287 kilograms of methane

1 gram of U-235 has the same amount of energy as 1287 kilograms of methane.

Hence option D is correct,

To learn more about uranium refer to the link;

brainly.com/question/9099776

#SPJ1

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Answer:

160 m

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Hence,

I_1r_1^2 = I_2r_2^2

r_2 = r_1\sqrt{\dfrac{I_1}{I_2}}

From the question, I_2 is half of I_1

r_2 = r_1\sqrt{\dfrac{I_1}{0.5I_1}}

r_2 = r_1\sqrt{2}

r_2 = 113\text{ m}\sqrt{2} = 160 \text{ m}

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2 years ago
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To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.

From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

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Where,

v_f = Final velocity

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F_f = F

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a = \mu_k g

Therefore,

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Re-arrange to find x,

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The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.

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Answer:

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2 years ago
The engine of a locomotive exerts a constant force of 8.1*10^5 N to accelerate a train to 68 km/h. Determine the time (in min) t
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gavmur [86]

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