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fiasKO [112]
3 years ago
8

The yield stress of a steel is 250Mpa. A steel rod used for implant in a femurneeds to withstand 29KN. What should the diameter

of the rod be not to deform
Engineering
1 answer:
OleMash [197]3 years ago
3 0

Answer:

r = 1.922 mm

Explanation:

We are given;

Yield stress; σ = 250 MPa = 250 N/mm²

Force; F = 29 KN = 29000 N

Now, formula for yield stress is;

σ = F/A

A = F/σ

Where A is area = πr²

Thus;

r² = 2900/250π

r² = 3.6924

r = √3.6924

r = 1.922 mm

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kap26 [50]

Answer:

The current through each lamp is 0.273 Amperes

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Explanation:

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3 years ago
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2 years ago
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