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3 years ago

As an engineer which types of ethical issues or problem you can face in industrial environment.

Engineering

1 answer:

Anarel [89]3 years ago

8 0

Explanation:

Answer ⬇️

Social and ethical issues in engineering, ethical principles of engineering, professional code of ethics, some specific social problems in engineering practice: privacy and data protection, corruption, user orientation, digital divide, human rights, access to basic services.

➡️dhruv73143(⌐■-■)

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both statement is correct

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so that both statement is correct

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3 years ago

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2 years ago

How to calculate the factor of your grade safety. explain

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Answer:

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2 years ago

A balanced three phase source with vL=240 V rms is supplying 8 kVA at 0.6 powder factor lagging to two wye connected parallel lo

xeze [42]

Answer:

2.35 + j8.34 Ω

Explanation:

Voltage = V $_{L}$ = 240 V rms

supplying power = S $_{s}$ = 8 kVA

power factor = pf $_{s}$ = 0.6

Let P₁ represents one load draws 3kW at unity powder factor

The power angle is:

θ $_{s}$ = cos⁻¹ pf $_{s}$ = cos⁻¹ 0.6 = 53.13°

Complex power supplied source is:

S $_{s}$ = S $_{s}$ < θ $_{s}$ = 8<53.13° kVA

Complex power for first load:

S₁ = P₁ = 3kVA

Since the power angle of first load is θ₁ = 0°

According to principle of conservation of AC power, the power of second load is:

S₂ = S $_{s}$ - S₁

= 8<53.13° - 3

= 6.65<74.29° kVA

Since the second load is a Y connected load the phase voltage:

V $_{p}$ = V $_{L}$ / $\sqrt{3}$

= 240/1.732051

= 138.564

= 138.56 V

Complex power of second load:

S₂ = 3 V $_{p}$ ² / Z $_{p}$

impedance per phase of the second load:

Z $_{p}$ = 3 V $_{p}$ ² / S₂

= 3 (138.56)² / 6.65<74.29°

= 3(19198.8736) / 6.65<74.29°

= 57596.6208 / 6.65<74.29°

Z $_{p}$ = 2.35 + j8.34Ω

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3 years ago