Answer:
The maximum allowable distance = 5 m
Explanation:
Data:
There will be three forces on the jib. Let the forces be denoted as:
,
and the force on pole AB
To find the angle AB makes with the horizontal beam:
The load has a mass of 2 000 kg then, the force will be:
F = mg, where g = 9.81 m/s²
=
Breaking AB into its x and y coordinates:
Then,
∑ = 0
∑
∑
so the components of the forces will be 30 656.2 N and - 3 372.18 N
Answer:
The inside temperature, is approximately 248 °C.
Explanation:
The parameters given are;
Temperature of the air = 20°C
Carbon steel surface temperature 250°C
Area of surface = 50 cm × 75 cm = 0.5 × 0.75 = 0.375 m²
Convection heat transfer coefficient = 25 W/(m²·K)
Heat lost by radiation = 300 W
Assumption,
Air temperature = 20 °C
Hot plate temperature = 250 °C
Thermal conductivity K = 65.2 W/(m·K)
Steady state heat transfer process
One dimensional heat conduction
We have;
Newton's law of cooling;
q = h×A×( -
) + Heat loss by radiation
= 25×0.325×(250 - 20) + 300
= 2456.25 W
The rate of energy transfer per second is given by the following relation;
Thermal conductivity K = 65.2 W/(m·K)
Therefore;
The inside temperature, = 247.99 °C ≈ 248 °C.