c. 1.5 moles of Cu will contain a total of 9.0 * 10 ^ 23 atoms.
Explanation:
To convert moles into atoms, the molar amount and number of atom is multiplied by Avagadro's number.
Avagadro's number is 6.022×
So applying the formula in the given sample:
A) 0.5×6.022×
3.01× atoms.
B) 0.75 mole of H20
O.75×6.022×
= 4.5166× atoms.
C) 1.5 moles of Cu
1.5×6.022×
= 9.033×
D). 1.5 moles of H2
1.5 × 2 × 6.022 ×
= 18.066 × atoms because H2 is 2 moles of hydrogen.
Atom is the smallest entity of matter having property of the element to which it is a part.
Energy required to vaporize : 32.3 kJ
<h3>Further explanation
</h3>
The heat to change the phase can be formulated :
Q = mLf (melting/freezing)
Q = mLv (vaporization/condensation)
Lf=latent heat of fusion
Lv=latent heat of vaporization
Mass of water = 14.27 g
Latent heat of vaporization
( boiling point of 100 ºC) : 2260 J/g
Energy required :
Answer: The purpose of a hypothesis is to find the answer to a question.
Explanation:
A hypothesis is a statement which is written as a source of prediction which is based upon the assumption of the cause of a natural event or process. The purpose of the hypothesis is basically to find the relevant answers to the scientific question. It is based upon few evidences and the entire statement of the hypothesis is tested using experimental procedures.
Answer:
It means there are 6 O2 molecules
Explanation:
Answer: The value of K for this reaction is 1.6875
Explanation:
Moles of 
= 4.0 mole
Volume of solution = 2.0 L
Initial concentration of = 
The given balanced equilibrium reaction is,
Initial conc. 2 M 0 M 0 M
At eqm. conc. (2-2x) M (x) M (3x) M
Equilibrium concentration of = 
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[x]\times [3x]^3}{[(2-2x)]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5Bx%5D%5Ctimes%20%5B3x%5D%5E3%7D%7B%5B%282-2x%29%5D%5E2%7D)
(2-2x) = 1.0
x= 0.5 M
Now put all the given values in this expression, we get :
![K_c=\frac{[0.5]\times [3\times 0.5]^3}{[(2-2\times 0.5)]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5B0.5%5D%5Ctimes%20%5B3%5Ctimes%200.5%5D%5E3%7D%7B%5B%282-2%5Ctimes%200.5%29%5D%5E2%7D)
Thus the value of K for this reaction is 1.6875
